Fix step-over-{trips-on-watchpoint|lands-on-breakpoint}.exp race

On a target that is both always in non-stop mode and can do displaced
stepping (such as native x86_64 GNU/Linux, with "maint set
target-non-stop on"), the step-over-trips-on-watchpoint.exp test
sometimes fails like this:

   (gdb) PASS: gdb.threads/step-over-trips-on-watchpoint.exp: no thread-specific bp: step: thread 1
   set scheduler-locking off
   (gdb) PASS: gdb.threads/step-over-trips-on-watchpoint.exp: no thread-specific bp: step: set scheduler-locking off
   step
  -[Switching to Thread 0x7ffff7fc0700 (LWP 11782)]
  -Hardware watchpoint 4: watch_me
  -
  -Old value = 0
  -New value = 1
  -child_function (arg=0x0) at /home/pedro/gdb/mygit/src/gdb/testsuite/gdb.threads/step-over-trips-on-watchpoint.c:39
  -39           other = 1; /* set thread-specific breakpoint here */
  -(gdb) PASS: gdb.threads/step-over-trips-on-watchpoint.exp: no thread-specific bp: step: step
  +wait_threads () at /home/pedro/gdb/mygit/src/gdb/testsuite/gdb.threads/step-over-trips-on-watchpoint.c:49
  +49       return 1; /* in wait_threads */
  +(gdb) FAIL: gdb.threads/step-over-trips-on-watchpoint.exp: no thread-specific bp: step: step

Note "scheduler-locking" was set off.  The problem is that on such
targets, the step-over of thread 2 and the "step" of thread 1 can be
set to run simultaneously (since with displaced stepping the
breakpoint isn't ever removed from the target), and sometimes, the
"step" of thread 1 finishes first, so it'd take another resume to see
the watchpoint trigger.  Fix this by replacing the wait_threads
function with a one-line infinite loop that doesn't call any function,
so that the "step" of thread 1 never finishes.

gdb/testsuite/ChangeLog:
2015-08-07  Pedro Alves  <palves@redhat.com>

	* gdb.threads/step-over-lands-on-breakpoint.c (wait_threads):
	Delete function.
	(main): Add alarm.  Run an infinite loop instead of calling
	wait_threads.
	* gdb.threads/step-over-lands-on-breakpoint.exp (do_test): Change
	comment.
	* gdb.threads/step-over-trips-on-watchpoint.c (wait_threads):
	Delete function.
	(main): Add alarm.  Run an infinite loop instead of calling
	wait_threads.
	* gdb.threads/step-over-trips-on-watchpoint.exp (do_test): Change
	comment.
This commit is contained in:
Pedro Alves 2015-08-06 18:22:59 +01:00
parent bfedc46af3
commit d4569d7bc5
5 changed files with 42 additions and 22 deletions

View File

@ -1,3 +1,18 @@
2015-08-07 Pedro Alves <palves@redhat.com>
* gdb.threads/step-over-lands-on-breakpoint.c (wait_threads):
Delete function.
(main): Add alarm. Run an infinite loop instead of calling
wait_threads.
* gdb.threads/step-over-lands-on-breakpoint.exp (do_test): Change
comment.
* gdb.threads/step-over-trips-on-watchpoint.c (wait_threads):
Delete function.
(main): Add alarm. Run an infinite loop instead of calling
wait_threads.
* gdb.threads/step-over-trips-on-watchpoint.exp (do_test): Change
comment.
2015-08-07 Pedro Alves <palves@redhat.com>
* gdb.base/checkpoint-ns.exp: New file.

View File

@ -41,23 +41,26 @@ child_function (void *arg)
pthread_exit (NULL);
}
static int
wait_threads (void)
{
return 1; /* in wait_threads */
}
int
main ()
{
int res;
long i;
alarm (300);
pthread_barrier_init (&barrier, NULL, 2);
res = pthread_create (&child_thread, NULL, child_function, NULL);
pthread_barrier_wait (&barrier);
wait_threads (); /* set wait-thread breakpoint here */
/* Use an infinite loop with no function calls so that "step" over
this line never finishes before the breakpoint in the other
thread triggers. That can happen if the step-over of thread 2 is
done with displaced stepping on a target that is always in
non-stop mode, as in that case GDB runs both threads
simultaneously. */
while (1); /* set wait-thread breakpoint here */
pthread_join (child_thread, NULL);

View File

@ -59,9 +59,9 @@ proc do_test {displaced command} {
gdb_test_no_output "set scheduler-locking off"
# Thread 2 is still stopped at a breakpoint that needs to be
# stepped over before proceeding thread 1. However, right
# where the step-over lands there's another breakpoint
# installed, which should trap and be reported to the user.
# stepped over. However, right where the step-over lands
# there's another breakpoint installed, which should trap and
# be reported to the user.
gdb_test "$command" "step-over here.*"
}
}

View File

@ -43,23 +43,26 @@ child_function (void *arg)
pthread_exit (NULL);
}
static int
wait_threads (void)
{
return 1; /* in wait_threads */
}
int
main ()
{
int res;
long i;
alarm (300);
pthread_barrier_init (&barrier, NULL, 2);
res = pthread_create (&child_thread, NULL, child_function, NULL);
pthread_barrier_wait (&barrier);
wait_threads (); /* set wait-thread breakpoint here */
/* Use an infinite loop with no function calls so that "step" over
this line never finishes before the watchpoint in the other
thread triggers. That can happen if the step-over of thread 2 is
done with displaced stepping on a target that is always in
non-stop mode, as in that case GDB runs both threads
simultaneously. */
while (1); /* set wait-thread breakpoint here */
pthread_join (child_thread, NULL);

View File

@ -115,11 +115,10 @@ proc do_test { displaced with_bp } {
gdb_test "thread 1" "Switching to .*"
gdb_test_no_output "set scheduler-locking off"
# Thread 2 is still stopped at a breakpoint that needs to be
# stepped over before proceeding thread 1. However, the
# instruction that is under the breakpoint triggers a
# watchpoint, which should trap and be reported to the
# user.
# Thread 2 is still stopped at a breakpoint that needs
# to be stepped over. However, the instruction that
# is under the breakpoint triggers a watchpoint, which
# should trap and be reported to the user.
gdb_test "$command" "Hardware watchpoint.*: watch_me.*New value = 1.*"
}
}