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* ada-lang.c (ada_delta): Change the type of numerators and

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denominators to DOUBLEST, as they may not fit into a long.
        (scaling_factor): Ditto.
This commit is contained in:
Joel Brobecker 2009-03-13 01:28:05 +00:00
parent 5c20fa2ae3
commit facc390f02
2 changed files with 23 additions and 7 deletions
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6
gdb/ChangeLog
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@ -1,3 +1,9 @@
2009-03-12 Jerome Guitton <guitton@adacore.com>
* ada-lang.c (ada_delta): Change the type of numerators and
denominators to DOUBLEST, as they may not fit into a long.
(scaling_factor): Ditto.
2009-03-12 Jerome Guitton <guitton@adacore.com>
* language.c (lang_bool_type): Set lai->bool_type_symbol to NULL.

24
gdb/ada-lang.c
View File

@ -9296,12 +9296,16 @@ DOUBLEST
ada_delta (struct type *type)
{
const char *encoding = fixed_type_info (type);
long num, den;
DOUBLEST num, den;
if (sscanf (encoding, "_%ld_%ld", &num, &den) < 2)
/* Strictly speaking, num and den are encoded as integer. However,
they may not fit into a long, and they will have to be converted
to DOUBLEST anyway. So scan them as DOUBLEST. */
if (sscanf (encoding, "_%" DOUBLEST_SCAN_FORMAT "_%" DOUBLEST_SCAN_FORMAT,
&num, &den) < 2)
return -1.0;
else
return (DOUBLEST) num / (DOUBLEST) den;
return num / den;
}
/* Assuming that ada_is_fixed_point_type (TYPE), return the scaling
@ -9311,17 +9315,23 @@ static DOUBLEST
scaling_factor (struct type *type)
{
const char *encoding = fixed_type_info (type);
unsigned long num0, den0, num1, den1;
DOUBLEST num0, den0, num1, den1;
int n;
n = sscanf (encoding, "_%lu_%lu_%lu_%lu", &num0, &den0, &num1, &den1);
/* Strictly speaking, num's and den's are encoded as integer. However,
they may not fit into a long, and they will have to be converted
to DOUBLEST anyway. So scan them as DOUBLEST. */
n = sscanf (encoding,
"_%" DOUBLEST_SCAN_FORMAT "_%" DOUBLEST_SCAN_FORMAT
"_%" DOUBLEST_SCAN_FORMAT "_%" DOUBLEST_SCAN_FORMAT,
&num0, &den0, &num1, &den1);
if (n < 2)
return 1.0;
else if (n == 4)
return (DOUBLEST) num1 / (DOUBLEST) den1;
return num1 / den1;
else
return (DOUBLEST) num0 / (DOUBLEST) den0;
return num0 / den0;
}