void abort (void);
#define N 500
int Z[2*N+2][2*N+2], B[2*N+2][2*N+2];
void foo(void)
{
int i,j;
for (i = 0; i < 2*N+2; i++)
for (j = 0; j < 2*N+2; j++)
B[i][j] = Z[i][j] = i + j;
for (i = 0; i <= N; i++)
for (j = 0; j <= N; j++)
Z[i][j] = Z[j+N][i+N+1];
for (j = 0; j <=N; j++)
if (Z[i][j] != B[j+N][i+N+1])
abort();
}
int main(void)
foo();
return 0;
/* Check that parallel code generation part make the right answer. */
/* { dg-final { scan-tree-dump-times "4 loops carried no dependency" 1 "graphite" } } */
/* { dg-final { scan-tree-dump-times "loopfn.0" 4 "optimized" } } */
/* { dg-final { scan-tree-dump-times "loopfn.1" 4 "optimized" } } */