i386: Remove REG_ALLOC_ORDER definition
REG_ALLOC_ORDER just defines what the default is set to. 2020-12-09 Uroš Bizjak <ubizjak@gmail.com> gcc/ * config/i386/i386.h (REG_ALLOC_ORDER): Remove
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@ -1163,22 +1163,6 @@ extern const char *host_detect_local_cpu (int argc, const char **argv);
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/* k0, k1, k2, k3, k4, k5, k6, k7*/ \
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1, 1, 1, 1, 1, 1, 1, 1 }
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/* Order in which to allocate registers. Each register must be
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listed once, even those in FIXED_REGISTERS. List frame pointer
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late and fixed registers last. Note that, in general, we prefer
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registers listed in CALL_USED_REGISTERS, keeping the others
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available for storage of persistent values.
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The ADJUST_REG_ALLOC_ORDER actually overwrite the order,
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so this is just empty initializer for array. */
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#define REG_ALLOC_ORDER \
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{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, \
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16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, \
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32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, \
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48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, \
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64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75 }
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/* ADJUST_REG_ALLOC_ORDER is a macro which permits reg_alloc_order
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to be rearranged based on a particular function. When using sse math,
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we want to allocate SSE before x87 registers and vice versa. */
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