c-decl.c (grokdeclarator): Instead of looking at TREE_OVERFLOW check if the constant fits in the index type.
2011-05-03 Richard Guenther <rguenther@suse.de> * c-decl.c (grokdeclarator): Instead of looking at TREE_OVERFLOW check if the constant fits in the index type. * gcc.dg/large-size-array-5.c: New testcase. From-SVN: r173297
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2011-05-03 Richard Guenther <rguenther@suse.de>
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* c-decl.c (grokdeclarator): Instead of looking at
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TREE_OVERFLOW check if the constant fits in the index type.
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2011-05-03 Richard Sandiford <richard.sandiford@linaro.org>
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* config/arm/neon.md (vec_load_lanes<mode><mode>): New expanders,
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gcc/c-decl.c
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gcc/c-decl.c
@ -5368,15 +5368,13 @@ grokdeclarator (const struct c_declarator *declarator,
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convert (index_type,
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size_one_node));
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/* If that overflowed, the array is too big. ???
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While a size of INT_MAX+1 technically shouldn't
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cause an overflow (because we subtract 1), the
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overflow is recorded during the conversion to
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index_type, before the subtraction. Handling
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this case seems like an unnecessary
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complication. */
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if (TREE_CODE (itype) == INTEGER_CST
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&& TREE_OVERFLOW (itype))
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/* The above overflows when size does not fit
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in index_type.
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??? While a size of INT_MAX+1 technically shouldn't
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cause an overflow (because we subtract 1), handling
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this case seems like an unnecessary complication. */
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if (TREE_CODE (size) == INTEGER_CST
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&& !int_fits_type_p (size, index_type))
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{
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if (name)
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error_at (loc, "size of array %qE is too large",
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@ -1,3 +1,7 @@
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2011-05-03 Richard Guenther <rguenther@suse.de>
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* gcc.dg/large-size-array-5.c: New testcase.
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2011-05-03 Richard Sandiford <richard.sandiford@linaro.org>
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* gcc.dg/vect/vect-strided-u16-i3.c: New test.
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9
gcc/testsuite/gcc.dg/large-size-array-5.c
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gcc/testsuite/gcc.dg/large-size-array-5.c
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/* { dg-do compile } */
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/* { dg-options "-Wno-overflow" } */
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typedef __SIZE_TYPE__ size_t;
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extern char a[((size_t)-1 >> 1) + 1]; /* { dg-error "too large" } */
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extern char b[((size_t)-1 >> 1)];
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extern int c[(((size_t)-1 >> 1) + 1) / sizeof(int)]; /* { dg-error "too large" } */
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extern int d[((size_t)-1 >> 1) / sizeof(int)];
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