(expand_expr, case ADDR_EXPR): Update temp slot address if we put it

in a register; mark result as pointer.

From-SVN: r6842
This commit is contained in:
Richard Kenner 1994-03-21 17:14:41 -05:00
parent 88bdba96d9
commit 987c71d9bc

View File

@ -5779,6 +5779,10 @@ expand_expr (exp, target, tmode, modifier)
return expand_increment (exp, ! ignore);
case ADDR_EXPR:
/* If nonzero, TEMP will be set to the address of something that might
be a MEM corresponding to a stack slot. */
temp = 0;
/* Are we taking the address of a nested function? */
if (TREE_CODE (TREE_OPERAND (exp, 0)) == FUNCTION_DECL
&& decl_function_context (TREE_OPERAND (exp, 0)) != 0)
@ -5803,6 +5807,8 @@ expand_expr (exp, target, tmode, modifier)
if (CONSTANT_P (op0))
op0 = force_const_mem (TYPE_MODE (TREE_TYPE (TREE_OPERAND (exp, 0))),
op0);
else if (GET_CODE (op0) == MEM)
temp = XEXP (op0, 0);
/* These cases happen in Fortran. Is that legitimate?
Should Fortran work in another way?
@ -5827,10 +5833,21 @@ expand_expr (exp, target, tmode, modifier)
if (modifier == EXPAND_SUM || modifier == EXPAND_INITIALIZER)
return XEXP (op0, 0);
op0 = force_operand (XEXP (op0, 0), target);
}
if (flag_force_addr && GET_CODE (op0) != REG)
return force_reg (Pmode, op0);
op0 = force_reg (Pmode, op0);
if (GET_CODE (op0) == REG)
mark_reg_pointer (op0);
/* If we might have had a temp slot, add an equivalent address
for it. */
if (temp != 0)
update_temp_slot_address (temp, op0);
return op0;
case ENTRY_VALUE_EXPR: