Test for gcov output.

* g77.dg/gcov: New directory.
	* g77.dg/gcov/gcov.exp: New file.
	* g77.dg/gcov/gcov-1.f: New test.
	* g77.dg/gcov/gcov-1.x: New file.

From-SVN: r45610
This commit is contained in:
Janis Johnson 2001-09-14 20:46:45 +00:00
parent 306220613d
commit 9b2641e729

View File

@ -0,0 +1,427 @@
C { dg-options "-fprofile-arcs -ftest-coverage" }
C { dg-do run { target native } }
C
C Test gcov reports for line counts and branch and call return percentages
C for various Fortran 77 constructs to catch basic regressions in the
C functionality.
program gcov1
implicit none
integer i,j,k,n
integer result
integer lpall, ieall, gtall
integer lpval, ieval, gtval
! returns(100)
lpval = lpall() ! count(1)
! returns(100)
ieval = ieall() ! count(1)
! returns(100)
gtval = gtall() ! count(1)
! returns(end)
if ((lpval .ne. 1) .or. (ieval .ne. 1) .or. (gtval .ne. 1)) then
call abort
end if
end
C Pass a value through a function to thwart optimization.
integer function foo(i)
implicit none
integer i
foo = i ! count(18)
end
C Test various flavors of GOTO and compare results against expected values.
integer function gtall()
implicit none
integer gt1, gt2, gt3, gt4, gt5
integer gtval
gtall = 1 ! count(1)
gtval = 0 ! count(1)
! returns(100)
gtval = gtval + gt1(0) ! count(1)
! returns(100)
gtval = gtval + gt1(1) ! count(1)
! returns(end)
! branch(0)
if (gtval .ne. 3) then ! count(1)
! branch(end)
print *,"gtall part 1: ", gtval, 3
gtall = 0
end if
gtval = 0 ! count(1)
! returns(100)
gtval = gtval + gt2(9) ! count(1)
! returns(100)
gtval = gtval + gt2(20) ! count(1)
! returns(end)
! branch(0)
if (gtval .ne. 12) then ! count(1)
! branch(end)
print *,"gtall part 2: ", gtval, 12
gtall = 0
end if
gtval = 0 ! count(1)
! returns(100)
gtval = gtval + gt3(0) ! count(1)
! returns(100)
gtval = gtval + gt3(3) ! count(1)
! returns(end)
! branch(0)
if (gtval .ne. 48) then ! count(1)
! branch(end)
! branch(end)
print *,"gtall part 3: ", gtval, 48
gtall = 0
end if
gtval = 0 ! count(1)
! returns(100)
gtval = gtval + gt4(1) ! count(1)
! returns(100)
gtval = gtval + gt4(2) ! count(1)
! returns(100)
gtval = gtval + gt4(3) ! count(1)
! returns(end)
! branch(0)
if (gtval .ne. 14) then ! count(1)
! branch(end)
print *,"gtall part 4: ", gtval, 14
gtall = 0
end if
gtval = 0 ! count(1)
! returns(100)
gtval = gtval + gt5(0) ! count(1)
! returns(100)
gtval = gtval + gt5(-1) ! count(1)
! returns(100)
gtval = gtval + gt5(5) ! count(1)
! returns(end)
! branch(0)
if (gtval .ne. 14) then ! count(1)
! branch(end)
print *,"gtall part 5: ", gtval, 14
gtall = 0
end if
end
C Test simple GOTO.
integer function gt1(f)
implicit none
integer f
! branch(50)
if (f .ne. 0) goto 100 ! count(2)
! branch(end)
gt1 = 1 ! count(1)
! branch(100)
goto 101 ! count(1)
! branch(end)
100 gt1 = 2 ! count(1)
101 continue ! count(2)
end
C Test simple GOTO again, this time out of a DO loop.
integer function gt2(f)
implicit none
integer f
integer i
! branch(95)
do i=1,10
! branch(end)
if (i .eq. f) goto 100 ! count(19)
end do
gt2 = 4 ! count(1)
! branch(100)
goto 101 ! count(1)
! branch(end)
100 gt2 = 8 ! count(1)
101 continue ! count(2)
end
C Test computed GOTO.
integer function gt3(i)
implicit none
integer i
goto (101, 102, 103, 104), i ! count(2)
gt3 = 8 ! count(1)
! branch(100)
goto 105 ! count(1)
! branch(end)
101 gt3 = 1024
goto 105
102 gt3 = 2048
goto 105
103 gt3 = 16 ! count(1)
! branch(100)
goto 105 ! count(1)
! branch(end)
104 gt3 = 4096
goto 105
105 gt3 = gt3 * 2 ! count(2)
end
C Test assigned GOTO.
integer function gt4(i)
implicit none
integer i
integer label
assign 101 to label ! count(3)
if (i .eq. 2) assign 102 to label ! count(3)
if (i .eq. 3) assign 103 to label ! count(3)
goto label, (101, 102, 103) ! count(3)
101 gt4 = 1 ! count(1)
goto 104 ! count(1)
102 gt4 = 2 ! count(1)
goto 104 ! count(1)
103 gt4 = 4 ! count(1)
104 gt4 = gt4 * 2 ! count(3)
end
C Test arithmetic IF (bundled with the GOTO variants).
integer function gt5(i)
implicit none
integer i
gt5 = 1 ! count(3)
! branch(67 50)
if (i) 101, 102, 103 ! count(3)
! branch(end)
101 gt5 = 2 ! count(1)
goto 104 ! count(1)
102 gt5 = 4 ! count(1)
goto 104 ! count(1)
103 gt5 = 8 ! count(1)
104 continue ! count(3)
end
C Run all of the loop tests and check results against expected values.
integer function lpall()
implicit none
integer loop1, loop2
integer loopval
lpall = 1 ! count(1)
loopval = 0 ! count(1)
! returns(100)
loopval = loopval + loop1(1,0) ! count(1)
! returns(100)
loopval = loopval + loop1(1,2) ! count(1)
! returns(100)
loopval = loopval + loop1(1,7) ! count(1)
! returns(end)
if (loopval .ne. 12) then ! count(1)
print *,"lpall part 1: ", loopval, 12
lpall = 0
end if
loopval = 0 ! count(1)
! returns(100)
loopval = loopval + loop2(1,0,0,0) ! count(1)
! returns(100)
loopval = loopval + loop2(1,1,0,0) ! count(1)
! returns(100)
loopval = loopval + loop2(1,1,3,0) ! count(1)
! returns(100)
loopval = loopval + loop2(1,1,3,1) ! count(1)
! returns(100)
loopval = loopval + loop2(1,3,1,5) ! count(1)
! returns(100)
loopval = loopval + loop2(1,3,7,3) ! count(1)
! returns(end)
if (loopval .ne. 87) then ! count(1)
print *,"lpall part 2: ", loopval, 87
lpall = 0
end if
end
C Test a simple DO loop.
integer function loop1(r,n)
implicit none
integer r,n,i
loop1 = r ! count(3)
! branch(75)
do i=1,n
! branch(end)
loop1 = loop1 + 1 ! count(9)
end do
end
C Test nested DO loops.
integer function loop2(r, l, m, n)
implicit none
integer r,l,m,n
integer i,j,k
loop2 = r ! count(6)
! branch(60)
do i=1,l
! branch(77)
do j=1,m
! branch(73)
do k=1,n
! branch(end)
loop2 = loop2 + 1 ! count(81)
end do
end do
end do
end
C Test various combinations of IF-THEN-ELSE and check results against
C expected values.
integer function ieall()
implicit none
integer ie1, ie2, ie3
integer ieval
ieall = 1 ! count(1)
ieval = 0 ! count(1)
ieval = ieval + ie1(0,2) ! count(1)
ieval = ieval + ie1(0,0) ! count(1)
ieval = ieval + ie1(1,2) ! count(1)
ieval = ieval + ie1(10,2) ! count(1)
ieval = ieval + ie1(11,11) ! count(1)
if (ieval .ne. 31) then ! count(1)
print *,"ieall part 1: ", ieval, 31
ieall = 0
end if
ieval = 0
ieval = ieval + ie2(0) ! count(1)
ieval = ieval + ie2(2) ! count(1)
ieval = ieval + ie2(2) ! count(1)
ieval = ieval + ie2(2) ! count(1)
ieval = ieval + ie2(3) ! count(1)
ieval = ieval + ie2(3) ! count(1)
if (ieval .ne. 23) then ! count(1)
print *,"ieall part 2: ", ieval, 23
ieall = 0
end if
ieval = 0
ieval = ieval + ie3(11,19) ! count(1)
ieval = ieval + ie3(25,27) ! count(1)
ieval = ieval + ie3(11,22) ! count(1)
ieval = ieval + ie3(11,10) ! count(1)
ieval = ieval + ie3(21,32) ! count(1)
ieval = ieval + ie3(21,20) ! count(1)
ieval = ieval + ie3(1,2) ! count(1)
ieval = ieval + ie3(32,31) ! count(1)
ieval = ieval + ie3(3,0) ! count(1)
ieval = ieval + ie3(0,47) ! count(1)
ieval = ieval + ie3(65,65) ! count(1)
if (ieval .ne. 246) then ! count(1)
print *,"ieall part 3: ", ieval, 246
ieall = 0
end if
end
C Test IF-THEN-ELSE.
integer function ie1(i,j)
implicit none
integer i,j
integer foo
ie1 = 0 ! count(5)
! branch(40)
if (i .ne. 0) then ! count(5)
! branch(0)
if (j .ne. 0) then ! count(3)
! branch(end)
ie1 = foo(4) ! count(3)
else
ie1 = foo(1024)
end if
else
! branch(50)
if (j .ne. 0) then ! count(2)
! branch(end)
ie1 = foo(1) ! count(1)
else
ie1 = foo(2) ! count(1)
end if
end if
! branch(80)
if (i .gt. j) then ! count(5)
! branch(end)
ie1 = foo(ie1*2)
end if
! branch(80)
if (i .gt. 10) then ! count(5)
! branch(0)
if (j .gt. 10) then ! count(1)
! branch(end)
ie1 = foo(ie1*4) ! count(1)
end if
end if
end
C Test a series of simple IF-THEN statements.
integer function ie2(i)
implicit none
integer i
integer foo
ie2 = 0 ! count(6)
! branch(83)
if (i .eq. 0) then ! count(6)
! branch(end)
ie2 = foo(1) ! count(1)
end if
! branch(100)
if (i .eq. 1) then ! count(6)
! branch(end)
ie2 = foo(1024)
end if
! branch(50)
if (i .eq. 2) then ! count(6)
! branch(end)
ie2 = foo(2) ! count(3)
end if
! branch(67)
if (i .eq. 3) then ! count(6)
! branch(end)
ie2 = foo(8) ! count(2)
end if
! branch(100)
if (i .eq. 4) then ! count(6)
! branch(end)
ie2 = foo(2048)
end if
end
C Test nested IF statements and IF with compound expressions.
integer function ie3(i,j)
implicit none
integer i,j
integer foo
ie3 = 1 ! count(11)
! branch(27 50 75)
if ((i .gt. 10) .and. (j .gt. i) .and. (j .lt. 20)) then ! count(11)
! branch(end)
ie3 = foo(16) ! count(1)
end if
! branch(55)
if (i .gt. 20) then ! count(11)
! branch(60)
if (j .gt. i) then ! count(5)
! branch(50)
if (j .lt. 30) then ! count(2)
! branch(end)
ie3 = foo(32) ! count(1)
end if
end if
end if
! branch(9 10 11)
if ((i .eq. 3) .or. (j .eq. 47) .or. (i .eq.j)) then ! count(11)
! branch(end)
ie3 = foo(64) ! count(3)
end if
end
C
C { dg-final { run-gcov -b gcov-1.f } }