re PR c++/39480 (generated memcpy causes trouble in assignment)
PR c++/39480 * call.c (build_over_call): Don't call memcpy if the target is the same as the source. From-SVN: r146013
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2009-04-13 Jason Merrill <jason@redhat.com>
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PR c++/39480
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* call.c (build_over_call): Don't call memcpy if the target is
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the same as the source.
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PR c++/39750
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* pt.c (uses_template_parms): Handle CONSTRUCTOR.
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@ -5391,17 +5391,33 @@ build_over_call (struct z_candidate *cand, int flags, tsubst_flags_t complain)
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else
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{
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/* We must only copy the non-tail padding parts.
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Use __builtin_memcpy for the bitwise copy. */
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Use __builtin_memcpy for the bitwise copy.
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FIXME fix 22488 so we can go back to using MODIFY_EXPR
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instead of an explicit call to memcpy. */
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tree arg0, arg1, arg2, t;
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tree test = NULL_TREE;
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arg2 = TYPE_SIZE_UNIT (as_base);
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arg1 = arg;
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arg0 = cp_build_unary_op (ADDR_EXPR, to, 0, complain);
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if (!(optimize && flag_tree_ter))
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{
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/* When TER is off get_pointer_alignment returns 0, so a call
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to __builtin_memcpy is expanded as a call to memcpy, which
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is invalid with identical args. When TER is on it is
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expanded as a block move, which should be safe. */
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arg0 = save_expr (arg0);
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arg1 = save_expr (arg1);
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test = build2 (EQ_EXPR, boolean_type_node, arg0, arg1);
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}
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t = implicit_built_in_decls[BUILT_IN_MEMCPY];
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t = build_call_n (t, 3, arg0, arg1, arg2);
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t = convert (TREE_TYPE (arg0), t);
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if (test)
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t = build3 (COND_EXPR, TREE_TYPE (t), test, arg0, t);
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val = cp_build_indirect_ref (t, 0, complain);
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}
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@ -1,5 +1,8 @@
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2009-04-13 Jason Merrill <jason@redhat.com>
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PR c++/39480
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* g++.dg/init/copy7.C: New.
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PR c++/39750
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* g++.dg/template/crash90.C: New.
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@ -0,0 +1,32 @@
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// PR c++/39480
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// It isn't always safe to call memcpy with identical arguments.
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// { dg-do run }
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extern "C" void abort();
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extern "C" void *
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memcpy(void *dest, void *src, __SIZE_TYPE__ n)
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{
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abort();
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}
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struct A
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{
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double d[10];
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};
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struct B: public A
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{
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char bc;
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};
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B b;
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void f(B *a1, B* a2)
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{
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*a1 = *a2;
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}
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int main()
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{
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f(&b,&b);
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}
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