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(simplify_plus_minus): Remove last change. 

(simplify_plus_minus): Remove last change.  Instead, count initial
operands and test against that count to see if we did anything.

From-SVN: r3748
This commit is contained in:
Richard Kenner 1993-03-15 17:38:40 -05:00
parent 682a59faae
commit b7d9299b30
1 changed files with 4 additions and 13 deletions
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17
gcc/cse.c
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@ -3928,7 +3928,7 @@ simplify_plus_minus (code, mode, op0, op1)
rtx ops[8];
int negs[8];
rtx result, tem;
int n_ops = 2;
int n_ops = 2, input_ops = 2;
int i, j, k;
int first = 1, negate = 0, changed;
@ -3956,6 +3956,7 @@ simplify_plus_minus (code, mode, op0, op1)
ops[n_ops] = XEXP (ops[i], 1);
negs[n_ops++] = GET_CODE (ops[i]) == MINUS ? !negs[i] : negs[i];
ops[i] = XEXP (ops[i], 0);
input_ops++;
changed = 1;
break;
@ -4015,17 +4016,7 @@ simplify_plus_minus (code, mode, op0, op1)
ncode = MINUS;
tem = simplify_binary_operation (ncode, mode, lhs, rhs);
/* If we got a simple object, a SUBREG of a simple
object, or a NEG, use it. Otherwise, we either got nothing
or we got something (like a NOT), which can cause an
infinite loop. */
if (tem != 0
&& ((GET_CODE (tem) == SUBREG
&& GET_RTX_CLASS (GET_CODE (SUBREG_REG (tem))) == 'o')
|| GET_CODE (tem) == NEG
|| GET_RTX_CLASS (GET_CODE (tem)) == 'o'))
if (tem)
{
ops[i] = tem, ops[j] = 0;
negs[i] = negs[i] && negs[j];
@ -4053,7 +4044,7 @@ simplify_plus_minus (code, mode, op0, op1)
k++;
}
if (i + k >= n_ops)
if (i + k >= input_ops)
return 0;
n_ops = i;