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c++: Remove ifdefed code 

The only reason I chose to use DECL_UID on this hash table was to make
it stable against ASLR and perturbations due to other allocations.
It's not required for correctness, as the comment mentions the
equality fn uses pointer identity.

	gcc/cp/
	* module.cc (struct duplicate_hash): Remove.
	(duplicate_hash_map): Adjust.
This commit is contained in:
Nathan Sidwell 2022-06-22 07:51:44 -07:00
parent d68d366425
commit d844478ab4
1 changed files with 1 additions and 15 deletions
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16
gcc/cp/module.cc
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@ -2829,24 +2829,10 @@ struct merge_key {
}
};
struct duplicate_hash : nodel_ptr_hash<tree_node>
{
#if 0
/* This breaks variadic bases in the xtreme_header tests. Since ::equal is
the default pointer_hash::equal, let's use the default hash as well. */
inline static hashval_t hash (value_type decl)
{
if (TREE_CODE (decl) == TREE_BINFO)
decl = TYPE_NAME (BINFO_TYPE (decl));
return hashval_t (DECL_UID (decl));
}
#endif
};
/* Hashmap of merged duplicates. Usually decls, but can contain
BINFOs. */
typedef hash_map<tree,uintptr_t,
simple_hashmap_traits<duplicate_hash,uintptr_t> >
simple_hashmap_traits<nodel_ptr_hash<tree_node>,uintptr_t> >
duplicate_hash_map;
/* Tree stream reader. Note that reading a stream doesn't mark the