1ad16c5284
Add compiler support for turning concatenating strings into a call to a runtime function that takes the appropriate number of arguments. Rename some local variables in mgc0.c to avoid macros that the new rune.go causes to appear in runtime.inc. Reviewed-on: https://go-review.googlesource.com/30827 From-SVN: r241074
220 lines
5.4 KiB
Go
220 lines
5.4 KiB
Go
/*
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* The authors of this software are Rob Pike and Ken Thompson.
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* Copyright (c) 2002 by Lucent Technologies.
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* Portions Copyright 2009 The Go Authors. All rights reserved.
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* Permission to use, copy, modify, and distribute this software for any
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* purpose without fee is hereby granted, provided that this entire notice
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* is included in all copies of any software which is or includes a copy
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* or modification of this software and in all copies of the supporting
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* documentation for such software.
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* THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED
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* WARRANTY. IN PARTICULAR, NEITHER THE AUTHORS NOR LUCENT TECHNOLOGIES MAKE ANY
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* REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY
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* OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE.
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*/
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/*
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* This code is copied, with slight editing due to type differences,
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* from a subset of ../lib9/utf/rune.c [which no longer exists]
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*/
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package runtime
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const (
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bit1 = 7
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bitx = 6
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bit2 = 5
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bit3 = 4
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bit4 = 3
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bit5 = 2
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t1 = ((1 << (bit1 + 1)) - 1) ^ 0xFF /* 0000 0000 */
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tx = ((1 << (bitx + 1)) - 1) ^ 0xFF /* 1000 0000 */
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t2 = ((1 << (bit2 + 1)) - 1) ^ 0xFF /* 1100 0000 */
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t3 = ((1 << (bit3 + 1)) - 1) ^ 0xFF /* 1110 0000 */
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t4 = ((1 << (bit4 + 1)) - 1) ^ 0xFF /* 1111 0000 */
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t5 = ((1 << (bit5 + 1)) - 1) ^ 0xFF /* 1111 1000 */
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rune1 = (1 << (bit1 + 0*bitx)) - 1 /* 0000 0000 0111 1111 */
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rune2 = (1 << (bit2 + 1*bitx)) - 1 /* 0000 0111 1111 1111 */
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rune3 = (1 << (bit3 + 2*bitx)) - 1 /* 1111 1111 1111 1111 */
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rune4 = (1 << (bit4 + 3*bitx)) - 1 /* 0001 1111 1111 1111 1111 1111 */
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maskx = (1 << bitx) - 1 /* 0011 1111 */
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testx = maskx ^ 0xFF /* 1100 0000 */
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runeerror = 0xFFFD
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runeself = 0x80
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surrogateMin = 0xD800
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surrogateMax = 0xDFFF
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bad = runeerror
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runemax = 0x10FFFF /* maximum rune value */
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)
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/*
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* Modified by Wei-Hwa Huang, Google Inc., on 2004-09-24
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* This is a slower but "safe" version of the old chartorune
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* that works on strings that are not necessarily null-terminated.
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*
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* If you know for sure that your string is null-terminated,
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* chartorune will be a bit faster.
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*
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* It is guaranteed not to attempt to access "length"
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* past the incoming pointer. This is to avoid
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* possible access violations. If the string appears to be
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* well-formed but incomplete (i.e., to get the whole Rune
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* we'd need to read past str+length) then we'll set the Rune
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* to Bad and return 0.
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*
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* Note that if we have decoding problems for other
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* reasons, we return 1 instead of 0.
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*/
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func charntorune(s string) (rune, int) {
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/* When we're not allowed to read anything */
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if len(s) <= 0 {
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return bad, 1
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}
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/*
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* one character sequence (7-bit value)
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* 00000-0007F => T1
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*/
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c := s[0]
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if c < tx {
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return rune(c), 1
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}
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// If we can't read more than one character we must stop
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if len(s) <= 1 {
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return bad, 1
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}
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/*
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* two character sequence (11-bit value)
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* 0080-07FF => t2 tx
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*/
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c1 := s[1] ^ tx
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if (c1 & testx) != 0 {
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return bad, 1
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}
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if c < t3 {
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if c < t2 {
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return bad, 1
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}
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l := ((rune(c) << bitx) | rune(c1)) & rune2
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if l <= rune1 {
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return bad, 1
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}
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return l, 2
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}
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// If we can't read more than two characters we must stop
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if len(s) <= 2 {
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return bad, 1
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}
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/*
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* three character sequence (16-bit value)
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* 0800-FFFF => t3 tx tx
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*/
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c2 := s[2] ^ tx
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if (c2 & testx) != 0 {
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return bad, 1
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}
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if c < t4 {
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l := ((((rune(c) << bitx) | rune(c1)) << bitx) | rune(c2)) & rune3
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if l <= rune2 {
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return bad, 1
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}
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if surrogateMin <= l && l <= surrogateMax {
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return bad, 1
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}
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return l, 3
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}
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if len(s) <= 3 {
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return bad, 1
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}
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/*
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* four character sequence (21-bit value)
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* 10000-1FFFFF => t4 tx tx tx
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*/
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c3 := s[3] ^ tx
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if (c3 & testx) != 0 {
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return bad, 1
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}
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if c < t5 {
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l := ((((((rune(c) << bitx) | rune(c1)) << bitx) | rune(c2)) << bitx) | rune(c3)) & rune4
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if l <= rune3 || l > runemax {
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return bad, 1
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}
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return l, 4
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}
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// Support for 5-byte or longer UTF-8 would go here, but
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// since we don't have that, we'll just return bad.
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return bad, 1
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}
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// runetochar converts r to bytes and writes the result to str.
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// returns the number of bytes generated.
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func runetochar(str []byte, r rune) int {
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/* runes are signed, so convert to unsigned for range check. */
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c := uint32(r)
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/*
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* one character sequence
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* 00000-0007F => 00-7F
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*/
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if c <= rune1 {
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str[0] = byte(c)
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return 1
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}
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/*
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* two character sequence
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* 0080-07FF => t2 tx
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*/
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if c <= rune2 {
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str[0] = byte(t2 | (c >> (1 * bitx)))
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str[1] = byte(tx | (c & maskx))
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return 2
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}
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/*
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* If the rune is out of range or a surrogate half, convert it to the error rune.
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* Do this test here because the error rune encodes to three bytes.
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* Doing it earlier would duplicate work, since an out of range
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* rune wouldn't have fit in one or two bytes.
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*/
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if c > runemax {
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c = runeerror
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}
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if surrogateMin <= c && c <= surrogateMax {
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c = runeerror
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}
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/*
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* three character sequence
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* 0800-FFFF => t3 tx tx
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*/
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if c <= rune3 {
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str[0] = byte(t3 | (c >> (2 * bitx)))
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str[1] = byte(tx | ((c >> (1 * bitx)) & maskx))
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str[2] = byte(tx | (c & maskx))
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return 3
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}
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/*
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* four character sequence (21-bit value)
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* 10000-1FFFFF => t4 tx tx tx
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*/
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str[0] = byte(t4 | (c >> (3 * bitx)))
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str[1] = byte(tx | ((c >> (2 * bitx)) & maskx))
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str[2] = byte(tx | ((c >> (1 * bitx)) & maskx))
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str[3] = byte(tx | (c & maskx))
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return 4
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}
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