de1e3b8795
With -pedantic the debug mode bitset has an ambiguous equality comparison operator, because it tries to compare the non-debug base to the debug object. The base object can be converted to another debug bitset, making the same operator== a candidate again. The fix is to do the comparison on both base objects, so the operator for the derived type isn't a candidate. For the inequality operator the same change should be done, but that operator can be removed entirely for C++20 because it can be synthesized by the compiler. I don't think either equality or inequality operators are really needed, because the public _GLIBCXX_STD_C::bitset base class cam always be compared using its own comparison operators. I'm not changing that here though. libstdc++-v3/ChangeLog: PR libstdc++/96303 * include/debug/bitset (bitset::operator==): Call _M_base() on right operand. (bitset::operator!=): Likewise, but don't define it at all when default comparisons are supported by the compiler. * testsuite/23_containers/bitset/operations/96303.cc: New test. |
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.. | ||
array | ||
assertions.h | ||
bitset | ||
debug.h | ||
deque | ||
formatter.h | ||
forward_list | ||
functions.h | ||
helper_functions.h | ||
list | ||
macros.h | ||
map | ||
map.h | ||
multimap.h | ||
multiset.h | ||
safe_base.h | ||
safe_container.h | ||
safe_iterator.h | ||
safe_iterator.tcc | ||
safe_local_iterator.h | ||
safe_local_iterator.tcc | ||
safe_sequence.h | ||
safe_sequence.tcc | ||
safe_unordered_base.h | ||
safe_unordered_container.h | ||
safe_unordered_container.tcc | ||
set | ||
set.h | ||
stl_iterator.h | ||
string | ||
unordered_map | ||
unordered_set | ||
vector |