171 lines
4.5 KiB
Go
171 lines
4.5 KiB
Go
// Copyright 2019 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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package math
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import "math/bits"
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func zero(x uint64) uint64 {
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if x == 0 {
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return 1
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}
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return 0
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// branchless:
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// return ((x>>1 | x&1) - 1) >> 63
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}
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func nonzero(x uint64) uint64 {
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if x != 0 {
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return 1
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}
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return 0
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// branchless:
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// return 1 - ((x>>1|x&1)-1)>>63
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}
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func shl(u1, u2 uint64, n uint) (r1, r2 uint64) {
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r1 = u1<<n | u2>>(64-n) | u2<<(n-64)
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r2 = u2 << n
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return
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}
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func shr(u1, u2 uint64, n uint) (r1, r2 uint64) {
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r2 = u2>>n | u1<<(64-n) | u1>>(n-64)
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r1 = u1 >> n
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return
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}
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// shrcompress compresses the bottom n+1 bits of the two-word
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// value into a single bit. the result is equal to the value
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// shifted to the right by n, except the result's 0th bit is
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// set to the bitwise OR of the bottom n+1 bits.
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func shrcompress(u1, u2 uint64, n uint) (r1, r2 uint64) {
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// TODO: Performance here is really sensitive to the
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// order/placement of these branches. n == 0 is common
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// enough to be in the fast path. Perhaps more measurement
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// needs to be done to find the optimal order/placement?
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switch {
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case n == 0:
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return u1, u2
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case n == 64:
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return 0, u1 | nonzero(u2)
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case n >= 128:
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return 0, nonzero(u1 | u2)
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case n < 64:
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r1, r2 = shr(u1, u2, n)
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r2 |= nonzero(u2 & (1<<n - 1))
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case n < 128:
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r1, r2 = shr(u1, u2, n)
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r2 |= nonzero(u1&(1<<(n-64)-1) | u2)
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}
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return
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}
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func lz(u1, u2 uint64) (l int32) {
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l = int32(bits.LeadingZeros64(u1))
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if l == 64 {
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l += int32(bits.LeadingZeros64(u2))
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}
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return l
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}
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// split splits b into sign, biased exponent, and mantissa.
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// It adds the implicit 1 bit to the mantissa for normal values,
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// and normalizes subnormal values.
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func split(b uint64) (sign uint32, exp int32, mantissa uint64) {
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sign = uint32(b >> 63)
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exp = int32(b>>52) & mask
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mantissa = b & fracMask
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if exp == 0 {
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// Normalize value if subnormal.
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shift := uint(bits.LeadingZeros64(mantissa) - 11)
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mantissa <<= shift
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exp = 1 - int32(shift)
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} else {
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// Add implicit 1 bit
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mantissa |= 1 << 52
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}
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return
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}
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// FMA returns x * y + z, computed with only one rounding.
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// (That is, FMA returns the fused multiply-add of x, y, and z.)
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func FMA(x, y, z float64) float64 {
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bx, by, bz := Float64bits(x), Float64bits(y), Float64bits(z)
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// Inf or NaN or zero involved. At most one rounding will occur.
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if x == 0.0 || y == 0.0 || z == 0.0 || bx&uvinf == uvinf || by&uvinf == uvinf {
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return x*y + z
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}
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// Handle non-finite z separately. Evaluating x*y+z where
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// x and y are finite, but z is infinite, should always result in z.
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if bz&uvinf == uvinf {
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return z
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}
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// Inputs are (sub)normal.
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// Split x, y, z into sign, exponent, mantissa.
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xs, xe, xm := split(bx)
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ys, ye, ym := split(by)
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zs, ze, zm := split(bz)
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// Compute product p = x*y as sign, exponent, two-word mantissa.
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// Start with exponent. "is normal" bit isn't subtracted yet.
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pe := xe + ye - bias + 1
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// pm1:pm2 is the double-word mantissa for the product p.
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// Shift left to leave top bit in product. Effectively
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// shifts the 106-bit product to the left by 21.
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pm1, pm2 := bits.Mul64(xm<<10, ym<<11)
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zm1, zm2 := zm<<10, uint64(0)
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ps := xs ^ ys // product sign
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// normalize to 62nd bit
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is62zero := uint((^pm1 >> 62) & 1)
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pm1, pm2 = shl(pm1, pm2, is62zero)
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pe -= int32(is62zero)
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// Swap addition operands so |p| >= |z|
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if pe < ze || (pe == ze && (pm1 < zm1 || (pm1 == zm1 && pm2 < zm2))) {
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ps, pe, pm1, pm2, zs, ze, zm1, zm2 = zs, ze, zm1, zm2, ps, pe, pm1, pm2
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}
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// Align significands
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zm1, zm2 = shrcompress(zm1, zm2, uint(pe-ze))
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// Compute resulting significands, normalizing if necessary.
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var m, c uint64
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if ps == zs {
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// Adding (pm1:pm2) + (zm1:zm2)
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pm2, c = bits.Add64(pm2, zm2, 0)
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pm1, _ = bits.Add64(pm1, zm1, c)
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pe -= int32(^pm1 >> 63)
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pm1, m = shrcompress(pm1, pm2, uint(64+pm1>>63))
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} else {
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// Subtracting (pm1:pm2) - (zm1:zm2)
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// TODO: should we special-case cancellation?
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pm2, c = bits.Sub64(pm2, zm2, 0)
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pm1, _ = bits.Sub64(pm1, zm1, c)
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nz := lz(pm1, pm2)
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pe -= nz
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m, pm2 = shl(pm1, pm2, uint(nz-1))
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m |= nonzero(pm2)
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}
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// Round and break ties to even
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if pe > 1022+bias || pe == 1022+bias && (m+1<<9)>>63 == 1 {
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// rounded value overflows exponent range
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return Float64frombits(uint64(ps)<<63 | uvinf)
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}
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if pe < 0 {
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n := uint(-pe)
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m = m>>n | nonzero(m&(1<<n-1))
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pe = 0
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}
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m = ((m + 1<<9) >> 10) & ^zero((m&(1<<10-1))^1<<9)
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pe &= -int32(nonzero(m))
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return Float64frombits(uint64(ps)<<63 + uint64(pe)<<52 + m)
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}
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