290 lines
6.9 KiB
ArmAsm
290 lines
6.9 KiB
ArmAsm
;; Copyright (C) 2001-2016 Free Software Foundation, Inc.
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;;
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;; This file is part of GCC.
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;;
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;; GCC is free software; you can redistribute it and/or modify it under
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;; the terms of the GNU General Public License as published by the Free
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;; Software Foundation; either version 3, or (at your option) any later
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;; version.
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;;
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;; GCC is distributed in the hope that it will be useful, but WITHOUT ANY
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;; WARRANTY; without even the implied warranty of MERCHANTABILITY or
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;; FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
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;; for more details.
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;;
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;; Under Section 7 of GPL version 3, you are granted additional
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;; permissions described in the GCC Runtime Library Exception, version
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;; 3.1, as published by the Free Software Foundation.
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;;
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;; You should have received a copy of the GNU General Public License and
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;; a copy of the GCC Runtime Library Exception along with this program;
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;; see the files COPYING3 and COPYING.RUNTIME respectively. If not, see
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;; <http://www.gnu.org/licenses/>.
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;;
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;; This code is derived from mulsi3.S, observing that the mstep*16-based
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;; multiplications there, from which it is formed, are actually
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;; zero-extending; in gcc-speak "umulhisi3". The difference to *this*
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;; function is just a missing top mstep*16 sequence and shifts and 64-bit
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;; additions for the high part. Compared to an implementation based on
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;; calling __Mul four times (see default implementation of umul_ppmm in
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;; longlong.h), this will complete in a time between a fourth and a third
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;; of that, assuming the value-based optimizations don't strike. If they
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;; all strike there (very often) but none here, we still win, though by a
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;; lesser margin, due to lesser total overhead.
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#define L(x) .x
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#define CONCAT1(a, b) CONCAT2(a, b)
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#define CONCAT2(a, b) a ## b
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#ifdef __USER_LABEL_PREFIX__
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# define SYM(x) CONCAT1 (__USER_LABEL_PREFIX__, x)
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#else
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# define SYM(x) x
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#endif
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.global SYM(__umulsidi3)
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.type SYM(__umulsidi3),@function
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SYM(__umulsidi3):
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#if defined (__CRIS_arch_version) && __CRIS_arch_version >= 10
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;; Can't have the mulu.d last on a cache-line, due to a hardware bug. See
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;; the documentation for -mmul-bug-workaround.
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;; Not worthwhile to conditionalize here.
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.p2alignw 2,0x050f
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mulu.d $r11,$r10
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ret
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move $mof,$r11
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#else
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move.d $r11,$r9
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bound.d $r10,$r9
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cmpu.w 65535,$r9
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bls L(L3)
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move.d $r10,$r12
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move.d $r10,$r13
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movu.w $r11,$r9 ; ab*cd = (a*c)<<32 (a*d + b*c)<<16 + b*d
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;; We're called for floating point numbers very often with the "low" 16
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;; bits zero, so it's worthwhile to optimize for that.
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beq L(L6) ; d == 0?
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lslq 16,$r13
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beq L(L7) ; b == 0?
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clear.w $r10
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mstep $r9,$r13 ; d*b
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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mstep $r9,$r13
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L(L7):
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test.d $r10
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mstep $r9,$r10 ; d*a
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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mstep $r9,$r10
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;; d*a in $r10, d*b in $r13, ab in $r12 and cd in $r11
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;; $r9 = d, need to do b*c and a*c; we can drop d.
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;; so $r9 is up for use and we can shift down $r11 as the mstep
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;; source for the next mstep-part.
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L(L8):
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lsrq 16,$r11
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move.d $r12,$r9
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lslq 16,$r9
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beq L(L9) ; b == 0?
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mstep $r11,$r9
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mstep $r11,$r9 ; b*c
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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mstep $r11,$r9
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L(L9):
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;; d*a in $r10, d*b in $r13, c*b in $r9, ab in $r12 and c in $r11,
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;; need to do a*c. We want that to end up in $r11, so we shift up $r11 to
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;; now use as the destination operand. We'd need a test insn to update N
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;; to do it the other way round.
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lsrq 16,$r12
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lslq 16,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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mstep $r12,$r11
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;; d*a in $r10, d*b in $r13, c*b in $r9, a*c in $r11 ($r12 free).
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;; Need (a*d + b*c)<<16 + b*d into $r10 and
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;; a*c + (a*d + b*c)>>16 plus carry from the additions into $r11.
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add.d $r9,$r10 ; (a*d + b*c) - may produce a carry.
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scs $r12 ; The carry corresponds to bit 16 of $r11.
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lslq 16,$r12
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add.d $r12,$r11 ; $r11 = a*c + carry from (a*d + b*c).
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#if defined (__CRIS_arch_version) && __CRIS_arch_version >= 8
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swapw $r10
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addu.w $r10,$r11 ; $r11 = a*c + (a*d + b*c) >> 16 including carry.
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clear.w $r10 ; $r10 = (a*d + b*c) << 16
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#else
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move.d $r10,$r9
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lsrq 16,$r9
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add.d $r9,$r11 ; $r11 = a*c + (a*d + b*c) >> 16 including carry.
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lslq 16,$r10 ; $r10 = (a*d + b*c) << 16
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#endif
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add.d $r13,$r10 ; $r10 = (a*d + b*c) << 16 + b*d - may produce a carry.
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scs $r9
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ret
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add.d $r9,$r11 ; Last carry added to the high-order 32 bits.
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L(L6):
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clear.d $r13
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ba L(L8)
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clear.d $r10
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L(L11):
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clear.d $r10
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ret
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clear.d $r11
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L(L3):
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;; Form the maximum in $r10, by knowing the minimum, $r9.
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;; (We don't know which one of $r10 or $r11 it is.)
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;; Check if the largest operand is still just 16 bits.
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xor $r9,$r10
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xor $r11,$r10
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cmpu.w 65535,$r10
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bls L(L5)
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movu.w $r9,$r13
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;; We have ab*cd = (a*c)<<32 + (a*d + b*c)<<16 + b*d, but c==0
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;; so we only need (a*d)<<16 + b*d with d = $r13, ab = $r10.
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;; Remember that the upper part of (a*d)<<16 goes into the lower part
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;; of $r11 and there may be a carry from adding the low 32 parts.
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beq L(L11) ; d == 0?
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move.d $r10,$r9
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lslq 16,$r9
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beq L(L10) ; b == 0?
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clear.w $r10
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mstep $r13,$r9 ; b*d
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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mstep $r13,$r9
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L(L10):
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test.d $r10
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mstep $r13,$r10 ; a*d
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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move.d $r10,$r11
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lsrq 16,$r11
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lslq 16,$r10
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add.d $r9,$r10
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scs $r12
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ret
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add.d $r12,$r11
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L(L5):
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;; We have ab*cd = (a*c)<<32 + (a*d + b*c)<<16 + b*d, but a and c==0
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;; so b*d (with min=b=$r13, max=d=$r10) it is. As it won't overflow the
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;; 32-bit part, just set $r11 to 0.
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lslq 16,$r10
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clear.d $r11
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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mstep $r13,$r10
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ret
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mstep $r13,$r10
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#endif
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L(Lfe1):
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.size SYM(__umulsidi3),L(Lfe1)-SYM(__umulsidi3)
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