gcc/libgo/go/runtime/rune.go
Ian Lance Taylor f8d9fa9e80 libgo, compiler: Upgrade libgo to Go 1.4, except for runtime.
This upgrades all of libgo other than the runtime package to
the Go 1.4 release.  In Go 1.4 much of the runtime was
rewritten into Go.  Merging that code will take more time and
will not change the API, so I'm putting it off for now.

There are a few runtime changes anyhow, to accomodate other
packages that rely on minor modifications to the runtime
support.

The compiler changes slightly to add a one-bit flag to each
type descriptor kind that is stored directly in an interface,
which for gccgo is currently only pointer types.  Another
one-bit flag (gcprog) is reserved because it is used by the gc
compiler, but gccgo does not currently use it.

There is another error check in the compiler since I ran
across it during testing.

gotools/:
	* Makefile.am (go_cmd_go_files): Sort entries.  Add generate.go.
	* Makefile.in: Rebuild.

From-SVN: r219627
2015-01-15 00:27:56 +00:00

220 lines
5.3 KiB
Go

/*
* The authors of this software are Rob Pike and Ken Thompson.
* Copyright (c) 2002 by Lucent Technologies.
* Portions Copyright 2009 The Go Authors. All rights reserved.
* Permission to use, copy, modify, and distribute this software for any
* purpose without fee is hereby granted, provided that this entire notice
* is included in all copies of any software which is or includes a copy
* or modification of this software and in all copies of the supporting
* documentation for such software.
* THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED
* WARRANTY. IN PARTICULAR, NEITHER THE AUTHORS NOR LUCENT TECHNOLOGIES MAKE ANY
* REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY
* OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE.
*/
/*
* This code is copied, with slight editing due to type differences,
* from a subset of ../lib9/utf/rune.c
*/
package runtime
const (
bit1 = 7
bitx = 6
bit2 = 5
bit3 = 4
bit4 = 3
bit5 = 2
t1 = ((1 << (bit1 + 1)) - 1) ^ 0xFF /* 0000 0000 */
tx = ((1 << (bitx + 1)) - 1) ^ 0xFF /* 1000 0000 */
t2 = ((1 << (bit2 + 1)) - 1) ^ 0xFF /* 1100 0000 */
t3 = ((1 << (bit3 + 1)) - 1) ^ 0xFF /* 1110 0000 */
t4 = ((1 << (bit4 + 1)) - 1) ^ 0xFF /* 1111 0000 */
t5 = ((1 << (bit5 + 1)) - 1) ^ 0xFF /* 1111 1000 */
rune1 = (1 << (bit1 + 0*bitx)) - 1 /* 0000 0000 0111 1111 */
rune2 = (1 << (bit2 + 1*bitx)) - 1 /* 0000 0111 1111 1111 */
rune3 = (1 << (bit3 + 2*bitx)) - 1 /* 1111 1111 1111 1111 */
rune4 = (1 << (bit4 + 3*bitx)) - 1 /* 0001 1111 1111 1111 1111 1111 */
maskx = (1 << bitx) - 1 /* 0011 1111 */
testx = maskx ^ 0xFF /* 1100 0000 */
runeerror = 0xFFFD
runeself = 0x80
surrogateMin = 0xD800
surrogateMax = 0xDFFF
bad = runeerror
runemax = 0x10FFFF /* maximum rune value */
)
/*
* Modified by Wei-Hwa Huang, Google Inc., on 2004-09-24
* This is a slower but "safe" version of the old chartorune
* that works on strings that are not necessarily null-terminated.
*
* If you know for sure that your string is null-terminated,
* chartorune will be a bit faster.
*
* It is guaranteed not to attempt to access "length"
* past the incoming pointer. This is to avoid
* possible access violations. If the string appears to be
* well-formed but incomplete (i.e., to get the whole Rune
* we'd need to read past str+length) then we'll set the Rune
* to Bad and return 0.
*
* Note that if we have decoding problems for other
* reasons, we return 1 instead of 0.
*/
func charntorune(s string) (rune, int) {
/* When we're not allowed to read anything */
if len(s) <= 0 {
return bad, 1
}
/*
* one character sequence (7-bit value)
* 00000-0007F => T1
*/
c := s[0]
if c < tx {
return rune(c), 1
}
// If we can't read more than one character we must stop
if len(s) <= 1 {
return bad, 1
}
/*
* two character sequence (11-bit value)
* 0080-07FF => t2 tx
*/
c1 := s[1] ^ tx
if (c1 & testx) != 0 {
return bad, 1
}
if c < t3 {
if c < t2 {
return bad, 1
}
l := ((rune(c) << bitx) | rune(c1)) & rune2
if l <= rune1 {
return bad, 1
}
return l, 2
}
// If we can't read more than two characters we must stop
if len(s) <= 2 {
return bad, 1
}
/*
* three character sequence (16-bit value)
* 0800-FFFF => t3 tx tx
*/
c2 := s[2] ^ tx
if (c2 & testx) != 0 {
return bad, 1
}
if c < t4 {
l := ((((rune(c) << bitx) | rune(c1)) << bitx) | rune(c2)) & rune3
if l <= rune2 {
return bad, 1
}
if surrogateMin <= l && l <= surrogateMax {
return bad, 1
}
return l, 3
}
if len(s) <= 3 {
return bad, 1
}
/*
* four character sequence (21-bit value)
* 10000-1FFFFF => t4 tx tx tx
*/
c3 := s[3] ^ tx
if (c3 & testx) != 0 {
return bad, 1
}
if c < t5 {
l := ((((((rune(c) << bitx) | rune(c1)) << bitx) | rune(c2)) << bitx) | rune(c3)) & rune4
if l <= rune3 || l > runemax {
return bad, 1
}
return l, 4
}
// Support for 5-byte or longer UTF-8 would go here, but
// since we don't have that, we'll just return bad.
return bad, 1
}
// runetochar converts r to bytes and writes the result to str.
// returns the number of bytes generated.
func runetochar(str []byte, r rune) int {
/* runes are signed, so convert to unsigned for range check. */
c := uint32(r)
/*
* one character sequence
* 00000-0007F => 00-7F
*/
if c <= rune1 {
str[0] = byte(c)
return 1
}
/*
* two character sequence
* 0080-07FF => t2 tx
*/
if c <= rune2 {
str[0] = byte(t2 | (c >> (1 * bitx)))
str[1] = byte(tx | (c & maskx))
return 2
}
/*
* If the rune is out of range or a surrogate half, convert it to the error rune.
* Do this test here because the error rune encodes to three bytes.
* Doing it earlier would duplicate work, since an out of range
* rune wouldn't have fit in one or two bytes.
*/
if c > runemax {
c = runeerror
}
if surrogateMin <= c && c <= surrogateMax {
c = runeerror
}
/*
* three character sequence
* 0800-FFFF => t3 tx tx
*/
if c <= rune3 {
str[0] = byte(t3 | (c >> (2 * bitx)))
str[1] = byte(tx | ((c >> (1 * bitx)) & maskx))
str[2] = byte(tx | (c & maskx))
return 3
}
/*
* four character sequence (21-bit value)
* 10000-1FFFFF => t4 tx tx tx
*/
str[0] = byte(t4 | (c >> (3 * bitx)))
str[1] = byte(tx | ((c >> (2 * bitx)) & maskx))
str[2] = byte(tx | ((c >> (1 * bitx)) & maskx))
str[3] = byte(tx | (c & maskx))
return 4
}