104 lines
4.4 KiB
C
104 lines
4.4 KiB
C
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/*
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* IBM Accurate Mathematical Library
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* written by International Business Machines Corp.
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* Copyright (C) 2001 Free Software Foundation
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*
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* This program is free software; you can redistribute it and/or modify
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* it under the terms of the GNU Lesser General Public License as published by
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* the Free Software Foundation; either version 2.1 of the License, or
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* (at your option) any later version.
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*
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* This program is distributed in the hope that it will be useful,
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* but WITHOUT ANY WARRANTY; without even the implied warranty of
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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* GNU Lesser General Public License for more details.
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*
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* You should have received a copy of the GNU Lesser General Public License
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* along with this program; if not, write to the Free Software
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* Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
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*/
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/****************************************************************************/
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/* MODULE_NAME:mpsqrt.c */
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/* */
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/* FUNCTION:mpsqrt */
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/* fastiroot */
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/* */
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/* FILES NEEDED:endian.h mpa.h mpsqrt.h */
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/* mpa.c */
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/* Multi-Precision square root function subroutine for precision p >= 4. */
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/* The relative error is bounded by 3.501*r**(1-p), where r=2**24. */
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/* */
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/****************************************************************************/
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#include "endian.h"
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#include "mpa.h"
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/****************************************************************************/
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/* Multi-Precision square root function subroutine for precision p >= 4. */
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/* The relative error is bounded by 3.501*r**(1-p), where r=2**24. */
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/* Routine receives two pointers to Multi Precision numbers: */
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/* x (left argument) and y (next argument). Routine also receives precision */
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/* p as integer. Routine computes sqrt(*x) and stores result in *y */
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/****************************************************************************/
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double fastiroot(double);
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void __mpsqrt(mp_no *x, mp_no *y, int p) {
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#include "mpsqrt.h"
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int i,m,ex,ey;
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double dx,dy;
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mp_no
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mphalf = {0,{0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,
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0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,
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0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0}},
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mp3halfs = {0,{0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,
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0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,
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0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0}};
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mp_no mpxn,mpz,mpu,mpt1,mpt2;
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/* Prepare multi-precision 1/2 and 3/2 */
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mphalf.e =0; mphalf.d[0] =ONE; mphalf.d[1] =HALFRAD;
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mp3halfs.e=1; mp3halfs.d[0]=ONE; mp3halfs.d[1]=ONE; mp3halfs.d[2]=HALFRAD;
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ex=EX; ey=EX/2; __cpy(x,&mpxn,p); mpxn.e -= (ey+ey);
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__mp_dbl(&mpxn,&dx,p); dy=fastiroot(dx); __dbl_mp(dy,&mpu,p);
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__mul(&mpxn,&mphalf,&mpz,p);
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m=mp[p];
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for (i=0; i<m; i++) {
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__mul(&mpu,&mpu,&mpt1,p);
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__mul(&mpt1,&mpz,&mpt2,p);
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__sub(&mp3halfs,&mpt2,&mpt1,p);
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__mul(&mpu,&mpt1,&mpt2,p);
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__cpy(&mpt2,&mpu,p);
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}
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__mul(&mpxn,&mpu,y,p); EY += ey;
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return;
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}
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/***********************************************************/
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/* Compute a double precision approximation for 1/sqrt(x) */
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/* with the relative error bounded by 2**-51. */
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/***********************************************************/
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double fastiroot(double x) {
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union {int i[2]; double d;} p,q;
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double y,z, t;
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int n;
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static const double c0 = 0.99674, c1 = -0.53380, c2 = 0.45472, c3 = -0.21553;
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p.d = x;
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p.i[HIGH_HALF] = (p.i[HIGH_HALF] & 0x3FFFFFFF ) | 0x3FE00000 ;
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q.d = x;
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y = p.d;
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z = y -1.0;
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n = (q.i[HIGH_HALF] - p.i[HIGH_HALF])>>1;
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z = ((c3*z + c2)*z + c1)*z + c0; /* 2**-7 */
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z = z*(1.5 - 0.5*y*z*z); /* 2**-14 */
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p.d = z*(1.5 - 0.5*y*z*z); /* 2**-28 */
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p.i[HIGH_HALF] -= n;
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t = x*p.d;
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return p.d*(1.5 - 0.5*p.d*t);
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}
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