KVM: MMU: handle n_free_mmu_pages > n_alloc_mmu_pages in kvm_mmu_change_mmu_pages
kvm_mmu_change_mmu_pages mishandles the case where n_alloc_mmu_pages is smaller then n_free_mmu_pages, by not checking if the result of the subtraction is negative. Its a valid condition which can happen if a large number of pages has been recently freed. Signed-off-by: Marcelo Tosatti <mtosatti@redhat.com> Signed-off-by: Avi Kivity <avi@redhat.com>
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@ -1407,24 +1407,25 @@ static int kvm_mmu_zap_page(struct kvm *kvm, struct kvm_mmu_page *sp)
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*/
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void kvm_mmu_change_mmu_pages(struct kvm *kvm, unsigned int kvm_nr_mmu_pages)
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{
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int used_pages;
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used_pages = kvm->arch.n_alloc_mmu_pages - kvm->arch.n_free_mmu_pages;
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used_pages = max(0, used_pages);
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/*
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* If we set the number of mmu pages to be smaller be than the
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* number of actived pages , we must to free some mmu pages before we
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* change the value
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*/
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if ((kvm->arch.n_alloc_mmu_pages - kvm->arch.n_free_mmu_pages) >
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kvm_nr_mmu_pages) {
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int n_used_mmu_pages = kvm->arch.n_alloc_mmu_pages
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- kvm->arch.n_free_mmu_pages;
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while (n_used_mmu_pages > kvm_nr_mmu_pages) {
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if (used_pages > kvm_nr_mmu_pages) {
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while (used_pages > kvm_nr_mmu_pages) {
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struct kvm_mmu_page *page;
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page = container_of(kvm->arch.active_mmu_pages.prev,
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struct kvm_mmu_page, link);
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kvm_mmu_zap_page(kvm, page);
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n_used_mmu_pages--;
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used_pages--;
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}
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kvm->arch.n_free_mmu_pages = 0;
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}
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