staging: lustre: ldlm: remove 'first_enq' arg from ldlm_process_flock_lock()

it is only ever set to '1', so we can just assume that and remove the code.

Signed-off-by: NeilBrown <neilb@suse.com>
Reviewed-by: Andreas Dilger <andreas.dilger@intel.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
This commit is contained in:
NeilBrown 2017-10-23 11:53:49 +11:00 committed by Greg Kroah-Hartman
parent e8b1844a7e
commit 09d61fdb86
1 changed files with 2 additions and 13 deletions

View File

@ -121,15 +121,9 @@ ldlm_flock_destroy(struct ldlm_lock *lock, enum ldlm_mode mode, __u64 flags)
* It is also responsible for splitting a lock if a portion of the lock
* is released.
*
* If \a first_enq is 0 (ie, called from ldlm_reprocess_queue):
* - blocking ASTs have already been sent
*
* If \a first_enq is 1 (ie, called from ldlm_lock_enqueue):
* - blocking ASTs have not been sent yet, so list of conflicting locks
* would be collected and ASTs sent.
*/
static int ldlm_process_flock_lock(struct ldlm_lock *req, __u64 *flags,
int first_enq, enum ldlm_error *err,
enum ldlm_error *err,
struct list_head *work_list)
{
struct ldlm_resource *res = req->l_resource;
@ -197,11 +191,6 @@ reprocess:
if (!ldlm_flocks_overlap(lock, req))
continue;
if (!first_enq) {
reprocess_failed = 1;
continue;
}
if (*flags & LDLM_FL_BLOCK_NOWAIT) {
ldlm_flock_destroy(req, mode, *flags);
*err = -EAGAIN;
@ -607,7 +596,7 @@ granted:
/* We need to reprocess the lock to do merges or splits
* with existing locks owned by this process.
*/
ldlm_process_flock_lock(lock, &noreproc, 1, &err, NULL);
ldlm_process_flock_lock(lock, &noreproc, &err, NULL);
}
unlock_res_and_lock(lock);
return rc;