c6x: switch to NO_BOOTMEM

The c6x is already using memblock and does most of early memory
reservations with it, so it was only a matter of removing the bootmem
initialization and handover of the memory from memblock to bootmem.

Signed-off-by: Mike Rapoport <rppt@linux.vnet.ibm.com>
Signed-off-by: Mark Salter <msalter@redhat.com>
This commit is contained in:
Mike Rapoport 2018-06-25 12:02:34 +03:00 committed by Mark Salter
parent b59dfdaef1
commit 4d8106f029
2 changed files with 2 additions and 25 deletions

View File

@ -14,6 +14,7 @@ config C6X
select GENERIC_IRQ_SHOW
select HAVE_ARCH_TRACEHOOK
select HAVE_MEMBLOCK
select NO_BOOTMEM
select SPARSE_IRQ
select IRQ_DOMAIN
select OF

View File

@ -291,7 +291,6 @@ notrace void __init machine_init(unsigned long dt_ptr)
void __init setup_arch(char **cmdline_p)
{
int bootmap_size;
struct memblock_region *reg;
printk(KERN_INFO "Initializing kernel\n");
@ -348,16 +347,6 @@ void __init setup_arch(char **cmdline_p)
init_mm.end_data = memory_start;
init_mm.brk = memory_start;
/*
* Give all the memory to the bootmap allocator, tell it to put the
* boot mem_map at the start of memory
*/
bootmap_size = init_bootmem_node(NODE_DATA(0),
memory_start >> PAGE_SHIFT,
PAGE_OFFSET >> PAGE_SHIFT,
memory_end >> PAGE_SHIFT);
memblock_reserve(memory_start, bootmap_size);
unflatten_and_copy_device_tree();
c6x_cache_init();
@ -392,22 +381,9 @@ void __init setup_arch(char **cmdline_p)
/* Initialize the coherent memory allocator */
coherent_mem_init(dma_start, dma_size);
/*
* Free all memory as a starting point.
*/
free_bootmem(PAGE_OFFSET, memory_end - PAGE_OFFSET);
/*
* Then reserve memory which is already being used.
*/
for_each_memblock(reserved, reg) {
pr_debug("reserved - 0x%08x-0x%08x\n",
(u32) reg->base, (u32) reg->size);
reserve_bootmem(reg->base, reg->size, BOOTMEM_DEFAULT);
}
max_low_pfn = PFN_DOWN(memory_end);
min_low_pfn = PFN_UP(memory_start);
max_pfn = max_low_pfn;
max_mapnr = max_low_pfn - min_low_pfn;
/* Get kmalloc into gear */