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fuse: Kill fasync only if interrupt is queued in queue_interrupt() 

We should sent signal only in case of interrupt is really queued.  Not a
real problem, but this makes the code clearer and intuitive.

Signed-off-by: Kirill Tkhai <ktkhai@virtuozzo.com>
Signed-off-by: Miklos Szeredi <mszeredi@redhat.com>
This commit is contained in:
Kirill Tkhai 2018-11-08 12:05:20 +03:00 committed by Miklos Szeredi
parent 340617508d
commit 8da6e91832
1 changed files with 1 additions and 1 deletions
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2
fs/fuse/dev.c
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@ -480,9 +480,9 @@ static void queue_interrupt(struct fuse_iqueue *fiq, struct fuse_req *req)
if (list_empty(&req->intr_entry)) {
list_add_tail(&req->intr_entry, &fiq->interrupts);
wake_up_locked(&fiq->waitq);
kill_fasync(&fiq->fasync, SIGIO, POLL_IN);
}
spin_unlock(&fiq->waitq.lock);
kill_fasync(&fiq->fasync, SIGIO, POLL_IN);
}
static void request_wait_answer(struct fuse_conn *fc, struct fuse_req *req)