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libceph: don't try checking queue_work() return value 

queue_work() doesn't "fail to queue", it returns false if work was
already on a queue, which can't happen here since we allocate
event_work right before we queue it.  So don't bother at all.

Signed-off-by: Ilya Dryomov <ilya.dryomov@inktank.com>
Reviewed-by: Alex Elder <elder@linaro.org>
This commit is contained in:
Ilya Dryomov 2014-09-11 12:18:53 +04:00 committed by Ilya Dryomov
parent 03974e8177
commit 91883cd27c
1 changed files with 5 additions and 10 deletions
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15
net/ceph/osd_client.c
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@ -2358,26 +2358,21 @@ static void handle_watch_notify(struct ceph_osd_client *osdc,
if (event) {
event_work = kmalloc(sizeof(*event_work), GFP_NOIO);
if (!event_work) {
dout("ERROR: could not allocate event_work\n");
goto done_err;
pr_err("couldn't allocate event_work\n");
ceph_osdc_put_event(event);
return;
}
INIT_WORK(&event_work->work, do_event_work);
event_work->event = event;
event_work->ver = ver;
event_work->notify_id = notify_id;
event_work->opcode = opcode;
if (!queue_work(osdc->notify_wq, &event_work->work)) {
dout("WARNING: failed to queue notify event work\n");
goto done_err;
}
queue_work(osdc->notify_wq, &event_work->work);
}
return;
done_err:
ceph_osdc_put_event(event);
return;
bad:
pr_err("osdc handle_watch_notify corrupt msg\n");
}