x86: use explicit copy in vdso_gettimeofday()

Jeremy's gcc 3.4 seems to be unable to inline a 8 byte memcpy.  But the
vdso doesn't support external references.  Copy the structure members
of struct timezone explicitely instead.

Signed-off-by: Andi Kleen <ak@linux.intel.com>
Cc: Jeremy Fitzhardinge <jeremy@goop.org>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
This commit is contained in:
Andi Kleen 2008-05-14 16:10:42 -07:00 committed by Thomas Gleixner
parent 2ddfd20e7c
commit a1289643ad
1 changed files with 3 additions and 3 deletions

View File

@ -106,9 +106,9 @@ int __vdso_gettimeofday(struct timeval *tv, struct timezone *tz)
do_realtime((struct timespec *)tv);
tv->tv_usec /= 1000;
if (unlikely(tz != NULL)) {
/* This relies on gcc inlining the memcpy. We'll notice
if it ever fails to do so. */
memcpy(tz, &gtod->sys_tz, sizeof(struct timezone));
/* Avoid memcpy. Some old compilers fail to inline it */
tz->tz_minuteswest = gtod->sys_tz.tz_minuteswest;
tz->tz_dsttime = gtod->sys_tz.tz_dsttime;
}
return 0;
}