resources: handle overflow when aligning start of available area
If tmp.start is near ~0, ALIGN(tmp.start) may overflow, which would make us think there's more available space than there really is. We would likely return something that conflicts with a previous resource, which would cause a failure when allocate_resource() requests the newly- allocated region. Reference: https://bugzilla.redhat.com/show_bug.cgi?id=646027 Reported-by: Fabrice Bellet <fabrice@bellet.info> Signed-off-by: Bjorn Helgaas <bjorn.helgaas@hp.com> Signed-off-by: Jesse Barnes <jbarnes@virtuousgeek.org>
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@ -392,7 +392,7 @@ static int find_resource(struct resource *root, struct resource *new,
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void *alignf_data)
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{
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struct resource *this = root->child;
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struct resource tmp = *new, alloc;
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struct resource tmp = *new, avail, alloc;
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tmp.start = root->start;
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/*
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@ -410,15 +410,20 @@ static int find_resource(struct resource *root, struct resource *new,
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tmp.end = root->end;
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resource_clip(&tmp, min, max);
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tmp.start = ALIGN(tmp.start, align);
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alloc.start = alignf(alignf_data, &tmp, size, align);
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/* Check for overflow after ALIGN() */
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avail = *new;
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avail.start = ALIGN(tmp.start, align);
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avail.end = tmp.end;
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if (avail.start >= tmp.start) {
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alloc.start = alignf(alignf_data, &avail, size, align);
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alloc.end = alloc.start + size - 1;
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if (resource_contains(&tmp, &alloc)) {
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if (resource_contains(&avail, &alloc)) {
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new->start = alloc.start;
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new->end = alloc.end;
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return 0;
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}
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}
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if (!this)
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break;
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tmp.start = this->end + 1;
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