x86: Don't check for BIOS corruption in first 64K when there's no need to
Due to commit 781c5a67f1
it is
likely that the number of areas to scan for BIOS corruption is 0
-- especially when the first 64K is already reserved
(X86_RESERVE_LOW is 64K by default).
If that's the case then don't set up the scan.
Signed-off-by: Naga Chumbalkar <nagananda.chumbalkar@hp.com>
Cc: <stable@kernel.org>
LKML-Reference: <20110225202838.2229.71011.sendpatchset@nchumbalkar.americas.hpqcorp.net>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
This commit is contained in:
parent
5471262290
commit
a7bd1dafdc
|
@ -106,8 +106,8 @@ void __init setup_bios_corruption_check(void)
|
|||
addr += size;
|
||||
}
|
||||
|
||||
printk(KERN_INFO "Scanning %d areas for low memory corruption\n",
|
||||
num_scan_areas);
|
||||
if (num_scan_areas)
|
||||
printk(KERN_INFO "Scanning %d areas for low memory corruption\n", num_scan_areas);
|
||||
}
|
||||
|
||||
|
||||
|
@ -143,12 +143,12 @@ static void check_corruption(struct work_struct *dummy)
|
|||
{
|
||||
check_for_bios_corruption();
|
||||
schedule_delayed_work(&bios_check_work,
|
||||
round_jiffies_relative(corruption_check_period*HZ));
|
||||
round_jiffies_relative(corruption_check_period*HZ));
|
||||
}
|
||||
|
||||
static int start_periodic_check_for_corruption(void)
|
||||
{
|
||||
if (!memory_corruption_check || corruption_check_period == 0)
|
||||
if (!num_scan_areas || !memory_corruption_check || corruption_check_period == 0)
|
||||
return 0;
|
||||
|
||||
printk(KERN_INFO "Scanning for low memory corruption every %d seconds\n",
|
||||
|
|
Loading…
Reference in New Issue