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tracing: Don't print an extra separator of flags 

If __print_flags() is used after another __print_*() function, the
temp seq_file buffer will not be empty on entry, and the delimiter will
be printed even though there's just one field. We get something like:

	|S

instead of just:

	S

This is because the length of the temp seq buffer is used to determine
if the delimiter is printed or not. But this algorithm fails when
the seq buffer is not empty on entry, and the delimiter will be printed
because it thinks that a previous field was already printed.

Link: http://lkml.kernel.org/r/1329650167-480655-1-git-send-email-avagin@openvz.org

Signed-off-by: Andrew Vagin <avagin@openvz.org>
Cc: Ingo Molnar <mingo@redhat.com>
Cc: Frederic Weisbecker <fweisbec@gmail.com>
Signed-off-by: Steven Rostedt <rostedt@goodmis.org>
This commit is contained in:
Andrey Vagin 2012-02-19 14:16:07 +03:00 committed by Steven Rostedt
parent 09bda4432a
commit e404b321db
1 changed files with 4 additions and 2 deletions
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6
kernel/trace/trace_output.c
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@ -300,7 +300,7 @@ ftrace_print_flags_seq(struct trace_seq *p, const char *delim,
unsigned long mask;
const char *str;
const char *ret = p->buffer + p->len;
int i;
int i, first = 1;
for (i = 0; flag_array[i].name && flags; i++) {
@ -310,8 +310,10 @@ ftrace_print_flags_seq(struct trace_seq *p, const char *delim,
str = flag_array[i].name;
flags &= ~mask;
if (p->len && delim)
if (!first && delim)
trace_seq_puts(p, delim);
else
first = 0;
trace_seq_puts(p, str);
}