f6be75d03c
The ebase is relative to CKSEG0 not CAC_BASE. On a 32-bit kernel they are the same thing, for a 64-bit kernel they are not. It happens to kind of work on a 64-bit kernel as they both reference the same physical memory. However since the CPU uses the CKSEG0 base, determining if a J instruction will reach always gives the wrong result unless we use the same number the CPU uses. Signed-off-by: David Daney <ddaney@caviumnetworks.com> To: linux-mips@linux-mips.org Patchwork: http://patchwork.linux-mips.org/patch/1093/ Signed-off-by: Ralf Baechle <ralf@linux-mips.org> |
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