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hw/block/nvme: Simplify timestamp sum 

As the 'timestamp' variable is declared as a 48-bit bitfield,
we do not need to wrap the sum result.

Signed-off-by: Philippe Mathieu-Daudé <philmd@redhat.com>
Reviewed-by: Klaus Jensen <k.jensen@samsung.com>
Message-Id: <20201002075716.1657849-1-philmd@redhat.com>
Signed-off-by: Laurent Vivier <laurent@vivier.eu>
This commit is contained in:
Philippe Mathieu-Daudé 2020-10-02 09:57:16 +02:00 committed by Laurent Vivier
parent 32048d724d
commit 009f51df0e
1 changed files with 1 additions and 6 deletions
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7
hw/block/nvme.c
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@ -1280,12 +1280,7 @@ static inline uint64_t nvme_get_timestamp(const NvmeCtrl *n)
union nvme_timestamp ts;
ts.all = 0;
/*
* If the sum of the Timestamp value set by the host and the elapsed
* time exceeds 2^48, the value returned should be reduced modulo 2^48.
*/
ts.timestamp = (n->host_timestamp + elapsed_time) & 0xffffffffffff;
ts.timestamp = n->host_timestamp + elapsed_time;
/* If the host timestamp is non-zero, set the timestamp origin */
ts.origin = n->host_timestamp ? 0x01 : 0x00;