qapi: Assert in places where variants are not handled
We are getting closer to the point where we could use one union as the base or variant type within another union type (as long as there are no collisions between any possible combination of member names allowed across all discriminator choices). But until we get to that point, it is worth asserting that variants are not present in places where we are not prepared to handle them: when exploding a type into a parameter list, we do not expect variants. The qapi.py code is already checking this, via the older check_type() method; but someday we hope to get rid of that and move checking into QAPISchema*.check(). The two asserts added here make sure any refactoring still catches problems, and makes it locally obvious why we can iterate over only type.members without worrying about type.variants. Signed-off-by: Eric Blake <eblake@redhat.com> Message-Id: <1458254921-17042-2-git-send-email-eblake@redhat.com> Signed-off-by: Markus Armbruster <armbru@redhat.com>
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@ -2,7 +2,7 @@
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# QAPI command marshaller generator
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#
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# Copyright IBM, Corp. 2011
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# Copyright (C) 2014-2015 Red Hat, Inc.
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# Copyright (C) 2014-2016 Red Hat, Inc.
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#
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# Authors:
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# Anthony Liguori <aliguori@us.ibm.com>
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@ -30,6 +30,7 @@ def gen_call(name, arg_type, ret_type):
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argstr = ''
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if arg_type:
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assert not arg_type.variants
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for memb in arg_type.members:
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if memb.optional:
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argstr += 'has_%s, ' % c_name(memb.name)
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@ -59,6 +59,7 @@ def gen_event_send(name, arg_type):
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name=name)
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if arg_type and arg_type.members:
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assert not arg_type.variants
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ret += mcgen('''
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qov = qmp_output_visitor_new();
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v = qmp_output_get_visitor(qov);
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