hbitmap: Fix merge when b is empty, and result is not an alias of a
Nobody calls the function like this currently, but we neither prohibit or cope with this behavior. I decided to make the function cope with it. Signed-off-by: John Snow <jsnow@redhat.com> Reviewed-by: Max Reitz <mreitz@redhat.com> Message-id: 20190709232550.10724-8-jsnow@redhat.com Signed-off-by: John Snow <jsnow@redhat.com>
This commit is contained in:
parent
cf0cd293c6
commit
3bde4b010e
@ -785,8 +785,9 @@ bool hbitmap_can_merge(const HBitmap *a, const HBitmap *b)
|
||||
}
|
||||
|
||||
/**
|
||||
* Given HBitmaps A and B, let A := A (BITOR) B.
|
||||
* Bitmap B will not be modified.
|
||||
* Given HBitmaps A and B, let R := A (BITOR) B.
|
||||
* Bitmaps A and B will not be modified,
|
||||
* except when bitmap R is an alias of A or B.
|
||||
*
|
||||
* @return true if the merge was successful,
|
||||
* false if it was not attempted.
|
||||
@ -801,7 +802,13 @@ bool hbitmap_merge(const HBitmap *a, const HBitmap *b, HBitmap *result)
|
||||
}
|
||||
assert(hbitmap_can_merge(b, result));
|
||||
|
||||
if (hbitmap_count(b) == 0) {
|
||||
if ((!hbitmap_count(a) && result == b) ||
|
||||
(!hbitmap_count(b) && result == a)) {
|
||||
return true;
|
||||
}
|
||||
|
||||
if (!hbitmap_count(a) && !hbitmap_count(b)) {
|
||||
hbitmap_reset_all(result);
|
||||
return true;
|
||||
}
|
||||
|
||||
|
Loading…
Reference in New Issue
Block a user