stream: Traverse graph after modification
bdrv_cor_filter_drop() modifies the block graph. That means that other parties can also modify the block graph before it returns. Therefore, we cannot assume that the result of a graph traversal we did before remains valid afterwards. We should thus fetch `base` and `unfiltered_base` afterwards instead of before. Signed-off-by: Hanna Reitz <hreitz@redhat.com> Reviewed-by: Kevin Wolf <kwolf@redhat.com> Reviewed-by: Vladimir Sementsov-Ogievskiy <vsementsov@virtuozzo.com> Message-Id: <20211111120829.81329-2-hreitz@redhat.com> Signed-off-by: Kevin Wolf <kwolf@redhat.com> Message-Id: <20211115145409.176785-2-kwolf@redhat.com> Signed-off-by: Hanna Reitz <hreitz@redhat.com>
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@ -54,8 +54,8 @@ static int stream_prepare(Job *job)
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{
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StreamBlockJob *s = container_of(job, StreamBlockJob, common.job);
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BlockDriverState *unfiltered_bs = bdrv_skip_filters(s->target_bs);
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BlockDriverState *base = bdrv_filter_or_cow_bs(s->above_base);
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BlockDriverState *unfiltered_base = bdrv_skip_filters(base);
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BlockDriverState *base;
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BlockDriverState *unfiltered_base;
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Error *local_err = NULL;
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int ret = 0;
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@ -63,6 +63,9 @@ static int stream_prepare(Job *job)
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bdrv_cor_filter_drop(s->cor_filter_bs);
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s->cor_filter_bs = NULL;
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base = bdrv_filter_or_cow_bs(s->above_base);
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unfiltered_base = bdrv_skip_filters(base);
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if (bdrv_cow_child(unfiltered_bs)) {
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const char *base_id = NULL, *base_fmt = NULL;
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if (unfiltered_base) {
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