qemu-timer: introduce timer_deinit
In some cases, a timer was set to NULL so that we could check if it is initialized. Use the timer_list field instead, and add a timer_deinit function that NULLs it. It then makes sense that timer_del be a no-op (instead of a crasher) on such a de-initialized timer. It avoids the need to poke at the timerlist field to check if the timers are initialized. Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
This commit is contained in:
parent
65a81af8df
commit
cd1bd53a66
@ -594,6 +594,17 @@ static inline QEMUTimer *timer_new_ms(QEMUClockType type, QEMUTimerCB *cb,
|
||||
return timer_new(type, SCALE_MS, cb, opaque);
|
||||
}
|
||||
|
||||
/**
|
||||
* timer_deinit:
|
||||
* @ts: the timer to be de-initialised
|
||||
*
|
||||
* Deassociate the timer from any timerlist. You should
|
||||
* call timer_del before. After this call, any further
|
||||
* timer_del call cannot cause dangling pointer accesses
|
||||
* even if the previously used timerlist is freed.
|
||||
*/
|
||||
void timer_deinit(QEMUTimer *ts);
|
||||
|
||||
/**
|
||||
* timer_free:
|
||||
* @ts: the timer
|
||||
|
14
qemu-timer.c
14
qemu-timer.c
@ -342,6 +342,12 @@ void timer_init_tl(QEMUTimer *ts,
|
||||
ts->expire_time = -1;
|
||||
}
|
||||
|
||||
void timer_deinit(QEMUTimer *ts)
|
||||
{
|
||||
assert(ts->expire_time == -1);
|
||||
ts->timer_list = NULL;
|
||||
}
|
||||
|
||||
void timer_free(QEMUTimer *ts)
|
||||
{
|
||||
g_free(ts);
|
||||
@ -398,9 +404,11 @@ void timer_del(QEMUTimer *ts)
|
||||
{
|
||||
QEMUTimerList *timer_list = ts->timer_list;
|
||||
|
||||
qemu_mutex_lock(&timer_list->active_timers_lock);
|
||||
timer_del_locked(timer_list, ts);
|
||||
qemu_mutex_unlock(&timer_list->active_timers_lock);
|
||||
if (timer_list) {
|
||||
qemu_mutex_lock(&timer_list->active_timers_lock);
|
||||
timer_del_locked(timer_list, ts);
|
||||
qemu_mutex_unlock(&timer_list->active_timers_lock);
|
||||
}
|
||||
}
|
||||
|
||||
/* modify the current timer so that it will be fired when current_time
|
||||
|
Loading…
Reference in New Issue
Block a user