softfloat: fix floatx80 handling of NaN

The floatx80 format uses an explicit bit that should be taken into account
when converting to and from commonNaN format.

When converting to commonNaN, the explicit bit should be removed if it is
a 1, and a default NaN should be used if it is 0.

When converting from commonNan, the explicit bit should be added.

Signed-off-by: Aurelien Jarno <aurelien@aurel32.net>
This commit is contained in:
Aurelien Jarno 2011-04-20 13:04:22 +02:00
parent da26fdc314
commit e2f422047b
1 changed files with 16 additions and 7 deletions

View File

@ -603,9 +603,15 @@ static commonNaNT floatx80ToCommonNaN( floatx80 a STATUS_PARAM)
commonNaNT z;
if ( floatx80_is_signaling_nan( a ) ) float_raise( float_flag_invalid STATUS_VAR);
z.sign = a.high>>15;
z.low = 0;
z.high = a.low;
if ( a.low >> 63 ) {
z.sign = a.high >> 15;
z.low = 0;
z.high = a.low << 1;
} else {
z.sign = floatx80_default_nan_high >> 15;
z.low = 0;
z.high = floatx80_default_nan_low << 1;
}
return z;
}
@ -624,11 +630,14 @@ static floatx80 commonNaNToFloatx80( commonNaNT a STATUS_PARAM)
return z;
}
if (a.high)
z.low = a.high;
else
if (a.high >> 1) {
z.low = LIT64( 0x8000000000000000 ) | a.high >> 1;
z.high = ( ( (uint16_t) a.sign )<<15 ) | 0x7FFF;
} else {
z.low = floatx80_default_nan_low;
z.high = ( ( (uint16_t) a.sign )<<15 ) | 0x7FFF;
z.high = floatx80_default_nan_high;
}
return z;
}