If we're using the capstone disassembler, disassembly of a run of
instructions more than 32 bytes long disassembles the wrong data for
instructions beyond the 32 byte mark:
(qemu) xp /16x 0x100
0000000000000100: 0x00000005 0x54410001 0x00000001 0x00001000
0000000000000110: 0x00000000 0x00000004 0x54410002 0x3c000000
0000000000000120: 0x00000000 0x00000004 0x54410009 0x74736574
0000000000000130: 0x00000000 0x00000000 0x00000000 0x00000000
(qemu) xp /16i 0x100
0x00000100: 00000005 andeq r0, r0, r5
0x00000104: 54410001 strbpl r0, [r1], #-1
0x00000108: 00000001 andeq r0, r0, r1
0x0000010c: 00001000 andeq r1, r0, r0
0x00000110: 00000000 andeq r0, r0, r0
0x00000114: 00000004 andeq r0, r0, r4
0x00000118: 54410002 strbpl r0, [r1], #-2
0x0000011c: 3c000000 .byte 0x00, 0x00, 0x00, 0x3c
0x00000120: 54410001 strbpl r0, [r1], #-1
0x00000124: 00000001 andeq r0, r0, r1
0x00000128: 00001000 andeq r1, r0, r0
0x0000012c: 00000000 andeq r0, r0, r0
0x00000130: 00000004 andeq r0, r0, r4
0x00000134: 54410002 strbpl r0, [r1], #-2
0x00000138: 3c000000 .byte 0x00, 0x00, 0x00, 0x3c
0x0000013c: 00000000 andeq r0, r0, r0
Here the disassembly of 0x120..0x13f is using the data that is in
0x104..0x123.
This is caused by passing the wrong value to the read_memory_func().
The intention is that at this point in the loop the 'cap_buf' buffer
already contains 'csize' bytes of data for the instruction at guest
addr 'pc', and we want to read in an extra 'tsize' bytes. Those
extra bytes are therefore at 'pc + csize', not 'pc'. On the first
time through the loop 'csize' happens to be zero, so the initial read
of 32 bytes into cap_buf is correct and as long as the disassembly
never needs to read more data we return the correct information.
Use the correct guest address in the call to read_memory_func().
Cc: qemu-stable@nongnu.org
Fixes: https://bugs.launchpad.net/qemu/+bug/1900779
Signed-off-by: Peter Maydell <peter.maydell@linaro.org>
Reviewed-by: Philippe Mathieu-Daudé <f4bug@amsat.org>
Message-id: 20201022132445.25039-1-peter.maydell@linaro.org
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