Add remove_current_as_list to LinkedList's CursorMut

The `remove_current` method only returns the inner `T` and deallocates the list node. This is unnecessary for move operations, where the element is going to be linked back into this (or even a different) `LinkedList`. The `remove_current_as_list` method avoids this by returning the unlinked list node as a new single-element `LinkedList` structure .
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main() 2020-05-04 15:53:02 +02:00 committed by GitHub
parent 6318d24ad8
commit 1593e2b7df
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@ -1496,6 +1496,31 @@ impl<'a, T> CursorMut<'a, T> {
}
}
/// Removes the current element from the `LinkedList` without deallocating the list node.
///
/// The node that was removed is returned as a new `LinkedList` containing only this node.
/// The cursor is moved to point to the next element in the current `LinkedList`.
///
/// If the cursor is currently pointing to the "ghost" non-element then no element
/// is removed and `None` is returned.
#[unstable(feature = "linked_list_cursors", issue = "58533")]
pub fn remove_current_as_list(&mut self) -> Option<LinkedList<T>> {
let unlinked_node = self.current?;
unsafe {
self.current = unlinked_node.as_ref().next;
self.list.unlink_node(unlinked_node);
unlinked_node.as_mut().prev = None;
unlinked_node.as_mut().next = None;
Some(LinkedList {
head: Some(unlinked_node),
tail: Some(unlinked_node),
len: 1,
marker: PhantomData,
})
}
}
/// Inserts the elements from the given `LinkedList` after the current one.
///
/// If the cursor is pointing at the "ghost" non-element then the new elements are