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bitv: make benchmarks always return a value 

This makes sure that the benchmarked code does not get optimized away.
Also fixed a typo.

Fixes #12118.
This commit is contained in:
Vinzent Steinberg 2014-08-20 23:36:07 -04:00
parent 6de570f817
commit c94bf8bb68
1 changed files with 11 additions and 8 deletions
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19
src/libcollections/bitv.rs
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@ -2616,18 +2616,19 @@ mod tests {
let mut b1 = Bitv::with_capacity(BENCH_BITS, false);
let b2 = Bitv::with_capacity(BENCH_BITS, false);
b.iter(|| {
b1.union(&b2);
b1.union(&b2)
})
}
#[bench]
fn bench_btv_small_iter(b: &mut Bencher) {
fn bench_bitv_small_iter(b: &mut Bencher) {
let bitv = Bitv::with_capacity(uint::BITS, false);
b.iter(|| {
let mut _sum = 0;
let mut sum = 0;
for pres in bitv.iter() {
_sum += pres as uint;
sum += pres as uint;
}
sum
})
}
@ -2635,10 +2636,11 @@ mod tests {
fn bench_bitv_big_iter(b: &mut Bencher) {
let bitv = Bitv::with_capacity(BENCH_BITS, false);
b.iter(|| {
let mut _sum = 0;
let mut sum = 0;
for pres in bitv.iter() {
_sum += pres as uint;
sum += pres as uint;
}
sum
})
}
@ -2647,10 +2649,11 @@ mod tests {
let bitv = BitvSet::from_bitv(from_fn(BENCH_BITS,
|idx| {idx % 3 == 0}));
b.iter(|| {
let mut _sum = 0;
let mut sum = 0;
for idx in bitv.iter() {
_sum += idx;
sum += idx;
}
sum
})
}
}