Merge pull request #3659 from gmcabrita/fix-typos

Fixed a few typos in the tutorials.
This commit is contained in:
Brian Anderson 2012-10-04 14:15:18 -07:00
commit dcdf1ee698
2 changed files with 7 additions and 7 deletions

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@ -65,7 +65,7 @@ forbidden.
To take as an argument a fragment of Rust code, write `$` followed by a name
(for use on the right-hand side), followed by a `:`, followed by the sort of
fragment to match (the most common ones are `ident`, `expr`, `ty`, `pat`, and
`block`). Anything not preceeded by a `$` is taken literally. The standard
`block`). Anything not preceded by a `$` is taken literally. The standard
rules of tokenization apply,
So `($x:ident => (($e:expr)))`, though excessively fancy, would create a macro
@ -88,7 +88,7 @@ position).
Going back to the motivating example, suppose that we wanted each invocation
of `early_return` to potentially accept multiple "special" identifiers. The
syntax `$(...)*` accepts zero or more occurences of its contents, much like
syntax `$(...)*` accepts zero or more occurrences of its contents, much like
the Kleene star operator in regular expressions. It also supports a separator
token (a comma-separated list could be written `$(...),*`), and `+` instead of
`*` to mean "at least one".

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@ -47,7 +47,7 @@ In particular, there are currently two independent modules that provide
a message passing interface to Rust code: `core::comm` and `core::pipes`.
`core::comm` is an older, less efficient system that is being phased out
in favor of `pipes`. At some point the existing `core::comm` API will
be romoved and the user-facing portions of `core::pipes` will be moved
be removed and the user-facing portions of `core::pipes` will be moved
to `core::comm`. In this tutorial we will discuss `pipes` and ignore
the `comm` API.
@ -151,7 +151,7 @@ commonly used, which we will cover presently.
The simplest way to create a pipe is to use the `pipes::stream`
function to create a `(Chan, Port)` pair. In Rust parlance a 'channel'
is a sending endpoint of a pipe, and a 'port' is the recieving
is a sending endpoint of a pipe, and a 'port' is the receiving
endpoint. Consider the following example of performing two calculations
concurrently.
@ -183,7 +183,7 @@ let (chan, port): (Chan<int>, Port<int>) = stream();
~~~~
The channel will be used by the child task to send data to the parent task,
which will wait to recieve the data on the port. The next statement
which will wait to receive the data on the port. The next statement
spawns the child task.
~~~~
@ -307,7 +307,7 @@ unrecoverable within a single task - once a task fails there is no way
to "catch" the exception.
All tasks are, by default, _linked_ to each other, meaning their fate
is interwined, and if one fails so do all of them.
is intertwined, and if one fails so do all of them.
~~~
# use task::spawn;