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Use a more descriptive variable name.

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I'm currently reading the rust book and this variable name tripped me up.
Because it was called "input", I thought at first it might contain the line
read by read_line(). This new variable name will be more instructive to rust
beginners.
This commit is contained in:
Jake Hickey 2015-06-22 18:38:19 -04:00
parent 5c5753e876
commit deee268015
1 changed files with 3 additions and 3 deletions
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6
src/doc/trpl/error-handling.md
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@ -225,9 +225,9 @@ There's another way of doing this that's a bit nicer than `unwrap()`:
```rust,ignore ```rust,ignore
let mut buffer = String::new(); let mut buffer = String::new();
let input = io::stdin().read_line(&mut buffer) let num_bytes_read = io::stdin().read_line(&mut buffer)
.ok() .ok()
.expect("Failed to read line"); .expect("Failed to read line");
``` ```
`ok()` converts the `Result` into an `Option`, and `expect()` does the same `ok()` converts the `Result` into an `Option`, and `expect()` does the same