350036a0c7
This includes the type name, so is clear, and may be necessary. There doesn't seem to be an obviously cleaner way to pull out the literal text of the named type here. Fixes #2879
104 lines
2.0 KiB
Rust
104 lines
2.0 KiB
Rust
#![warn(default_trait_access)]
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use std::default::Default as D2;
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use std::string;
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use std::default;
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fn main() {
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let s1: String = Default::default();
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let s2 = String::default();
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let s3: String = D2::default();
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let s4: String = std::default::Default::default();
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let s5 = string::String::default();
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let s6: String = default::Default::default();
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let s7 = std::string::String::default();
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let s8: String = DefaultFactory::make_t_badly();
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let s9: String = DefaultFactory::make_t_nicely();
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let s10 = DerivedDefault::default();
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let s11: GenericDerivedDefault<String> = Default::default();
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let s12 = GenericDerivedDefault::<String>::default();
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let s13 = TupleDerivedDefault::default();
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let s14: TupleDerivedDefault = Default::default();
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let s15: ArrayDerivedDefault = Default::default();
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let s16 = ArrayDerivedDefault::default();
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let s17: TupleStructDerivedDefault = Default::default();
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let s18 = TupleStructDerivedDefault::default();
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let s19 = <DerivedDefault as Default>::default();
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println!(
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"[{}] [{}] [{}] [{}] [{}] [{}] [{}] [{}] [{}] [{:?}] [{:?}] [{:?}] [{:?}] [{:?}] [{:?}] [{:?}] [{:?}] [{:?}], [{:?}]",
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s1,
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s2,
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s3,
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s4,
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s5,
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s6,
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s7,
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s8,
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s9,
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s10,
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s11,
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s12,
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s13,
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s14,
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s15,
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s16,
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s17,
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s18,
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s19,
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);
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}
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struct DefaultFactory;
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impl DefaultFactory {
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pub fn make_t_badly<T: Default>() -> T {
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Default::default()
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}
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pub fn make_t_nicely<T: Default>() -> T {
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T::default()
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}
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}
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#[derive(Debug, Default)]
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struct DerivedDefault {
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pub s: String,
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}
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#[derive(Debug, Default)]
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struct GenericDerivedDefault<T: Default + std::fmt::Debug> {
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pub s: T,
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}
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#[derive(Debug, Default)]
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struct TupleDerivedDefault {
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pub s: (String, String),
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}
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#[derive(Debug, Default)]
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struct ArrayDerivedDefault {
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pub s: [String; 10],
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}
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#[derive(Debug, Default)]
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struct TupleStructDerivedDefault(String);
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