audio/sdlaudio: Simplify the sdl_callback function
At the end of the while-loop, either "samples" or "sdl->live" is zero, so now that we've removed the semaphore code, the content of the while-loop is always only executed once. Thus we can remove the while-loop now to get rid of one indentation level here. Signed-off-by: Thomas Huth <thuth@redhat.com> Message-id: 1549336101-17623-3-git-send-email-thuth@redhat.com Signed-off-by: Gerd Hoffmann <kraxel@redhat.com>
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@ -189,21 +189,14 @@ static void sdl_callback (void *opaque, Uint8 *buf, int len)
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SDLAudioState *s = &glob_sdl;
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HWVoiceOut *hw = &sdl->hw;
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int samples = len >> hw->info.shift;
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int to_mix, decr;
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if (s->exit) {
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if (s->exit || !sdl->live) {
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return;
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}
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while (samples) {
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int to_mix, decr;
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/* dolog ("in callback samples=%d live=%d\n", samples, sdl->live); */
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/* dolog ("in callback samples=%d\n", samples); */
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if (s->exit || !sdl->live) {
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break;
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}
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/* dolog ("in callback live=%d\n", live); */
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to_mix = audio_MIN(samples, sdl->live);
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decr = to_mix;
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while (to_mix) {
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@ -219,7 +212,7 @@ static void sdl_callback (void *opaque, Uint8 *buf, int len)
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samples -= decr;
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sdl->live -= decr;
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sdl->decr += decr;
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}
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/* dolog ("done len=%d\n", len); */
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/* SDL2 does not clear the remaining buffer for us, so do it on our own */
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